Charge Sharing & Loss of Energy

A capacitor of $20\ \mu$F is charged up to $500$ V is connected in parallel with another capacitor of $10\ \mu$F which is charged up to $200$ V. Then, the common potential will be

A condenser of capacity $C_1$ is charged to potential $V_1$ and then disconnected. Uncharged capacitor of capacity $C_2$ is connected in parallel with $C_1$. The resultant potential $V_2$ is

A capacitor $P$ with capacitance $10 \times 10^{-6}\text{ F}$ is fully charged with a potential difference of 6.0 V and disconnected from the battery. The charged capacitor $P$ is connected across another capacitor $Q$ with capacitance $20 \times 10^{-6}\text{ F}$. The charge on capacitor $Q$ when equilibrium is established will be $\alpha \times 10^{-5}\text{ C}$ (assume capacitor $Q$ does not have any charge initially), the value of $\alpha$ is ______.

Consider two uncharged capacitors of equal capacitance 200 pF. One of them is charged by a 100 V supply and disconnected. Now this capacitor is connected to the uncharged capacitor. The amount of electrostatic energy lost in the process is:

A sphere of capacitance 100 pF is charged to a potential of 100 V. Another identical uncharged metal sphere is brought in contact with the charged sphere, then the change in the total energy stored on these spheres, when they touch is $\alpha \times 10^{-7}\text{ J}$. The value of $\alpha$ is ______. (combined capacitance of spheres is 200 pF)

A parallel plate capacitor of capacitance 'C' is connected to a battery and charged to a potential 'V'. Another capacitor of capacitance '$3C$' is charged to a potential '$3V$'. The charging battery is then disconnected and both the capacitors are connected in parallel to each other such that positive terminal of one is connected to negative terminal of the other. The final energy of the configuration is

Two capacitors of $100\ \mu\text{F}$ and $50\ \mu\text{F}$ are connected in parallel. If the potential difference across $100\ \mu\text{F}$ is 20 V and across $50\ \mu\text{F}$ is 40 V, then the common potential of the parallel combination will be (same polarities of the capacitor connected together)

Using a battery, a 100 pF capacitor is charged to 60 V and then the battery is removed. After that, a second uncharged capacitor is connected to the first capacitor in parallel. If the final voltage across the second capacitor is 20 V, its capacitance is: (in pF)

A capacitor, $C_1 = 6\ \mu\text{F}$ is charged to a potential difference of $V_0 = 5\text{ V}$ using a 5V battery. The battery is removed and another capacitor, $C_2 = 12\ \mu\text{F}$ is inserted in place of the battery. When the switch 'S' is closed, the charge flows between the capacitors for some time until equilibrium condition is reached. What are the charges ($q_1$ and $q_2$) on the capacitors $C_1$ and $C_2$ when equilibrium condition is reached.

A capacitor of capacitance $C$ and potential $V$ has energy $E$. It is connected to another capacitor of capacitance $2C$ and potential $2V$. Then the loss of energy is $\frac{x}{3}E$, where $x$ is _______.

Two identical capacitors have the same capacitance ' $C$ '. One of them is charged to potential $V_1$ and other to $V_2$. The negative ends of capacitors are connected together. When positive ends are also connected, the decrease in energy of the combined system is

A parallel plate capacitor of capacitance ' $C$ ' is connected to a battery and charged to a potential difference ' $V$ '. Another capacitor of capacitance 3 C is similarly charged to a potential difference 3 V. The charging battery is then disconnected and capacitors are connected in parallel to each other in such a way that positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is

Two identical capacitors have same capacitance $C$. One of them is charged to the potential $V$ and other to the potential $2\text{ V}$. The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is:

A parallel plate capacitor of capacitance $2\text{ F}$ is charged to a potential $V$, The energy stored in the capacitor is $E_1$. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is $E_2$. The ratio $E_2/E_1$ is:

A $600\text{ pF}$ capacitor is charged by $200\text{ V}$ supply. It is then disconnected from the supply and is connected to another uncharged $600\text{ pF}$ capacitor. Electrostatic energy lost in the process is ____________ $\mu\text{J}$

Two identical capacitors have the same capacitance '$C$'. One of them is charged to a potential $V_1$ and the other to $V_2$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is

A capacitor of capacitance $900\ \mu\text{F}$ is charged by a $100\text{ V}$ battery. The capacitor is disconnected from the battery and connected to another uncharged identical capacitor such that one plate of uncharged capacitor connected to positive plate and another plate of uncharged capacitor connected to negative plate of the charged capacitor. The loss of energy in this process is measured as $x\times 10^{-2}\text{ J}$. The value of $x$ is _____________.

A capacitor of capacitance C = 900 pF is charged fully by 100 V battery B as shown in figure (a). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance C = 900 pF as shown in figure (b). The electrostatic energy stored by the system (b) is

A capacitor of capacitance 50 pF is charged by 100 V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is ___________ nJ.

Two capacitors having capacitance C1 and C2 respectively are connected as shown in figure. Initially, capacitor C1 is charged to a potential difference V volt by a battery. The battery is then removed and the charged capacitor C1 is now connected to uncharged capacitor C2 by closing the switch S. The amount of charge on the capacitor C2, after equilibrium, is:

A capacitor C1 of capacitance 5 $\mu$F is charged to a potential of 30 V using a battery. The battery is then removed and the charged capacitor is connected to an uncharged capacitor C2 of capacitance 10 $\mu$F as shown in figure. When the switch is closed charge flows between the capacitors. At equilibrium, the charge on the capacitor C2 is __________ $\mu$C.

A condenser of capacity '$C_1$' is charged to potential '$V_1$ ' and then disconnected. Uncharged capacitor of capacity '$C_2$' is connected in parallel with '$C_1$'. The resultant potential '$V_2$' is

A 2$\mu$F capacitor C1 is first charged to a potential difference of 10V using a battery. Then the battery is removed and the capacitor is connected to an uncharged capacitor C2 of 8 $\mu$F. The charge in C2 on equilibrium condition is ____________ $\mu$C. (Round off to the Nearest Integer)

Two identical capacitors have the same capacitance '$C$'. One of them is charged to potential '$V_1$' and the other to $V_2$. The negative ends of the capacitors are connected together. When positive ends are also connected, the decrease in energy of the combined system is

A 10 $\mu$F capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is:

A capacitor C is fully charged with voltage V0. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance $\frac{C}{2}$. The energy loss in the process after the charge is distributed between the two capacitors is:

A 60 pF capacitor is fully charged by a 20 V supply. It is then disconnected from the supply and is conneced to another uncharged 60 pF capacitor in parallel. The electrostatic energy that is lost in this process by the time the charge is redistributed between them is (in nJ) _____

A 5 $\mu$F capacitor is charged fully by a 220 V supply. It is then disconnected from the supply and is connected in series to another uncharged 2.5 $\mu$F capacitor. If the energy change during the charge redistribution is $\frac{X}{100}\text{ J}$ then value of X to the nearest integer is _____.

Two capacitors of capacitances C and 2C are charged to potential differences V and 2V, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is:

Two identical capacitors $C_1$ and $C_2$ of equal capacitance are connected as shown in the circuit. Terminals a and b of the key k are connected to charge capacitor $C_1$ using battery of emf V volt. Now disconnecting a and b the terminals b and c are connected. Due to this, what will be the percentage loss of energy?

In the figure shown, after the switch 'S' is turned from position 'A' to position 'B', the energy dissipated in the circuit in terms of capacitance 'C' and total charge 'Q' is:

A capacitor C1 = 1.0 $\mu$F is charged up to a voltage V = 60 V by connecting it to battery B through switch (1). Now C1 is disconnected from battery and connected to a circuit consisting of two uncharged capacitors $C_2=3.0\ \mu\text{F}$ and C3 = 6.0 $\mu$F through switch (2), as shown in the figure. The sum of final charges on C2 and C3 is:

A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of resulting system

A capacitor of 2 $\mu$F is charged as shown in the diagram. When the switch S is turned to position 2, the percentage of its stored energy dissipated is

Two capacitors $C_1$ and $C_2$ are charged to $120\text{ V}$ and $200\text{ V}$ respectively. It is found that connecting them together the potential on each one can be made zero. Then

A capacitor of capacity C1 charged upto V volt and then connected to an uncharged capacitor of capacity C2. The final potential difference across each will be

A capacitor is charged with a battery and energy stored is U. After disconnecting battery another capacitor of same capacity is connected in parallel to the first capacitor. Then energy stored in each capacitor is