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Scalar (Dot) Product

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Q1MHT CET 2026 · 19 MAY · SHIFT 2Easy

Scalar (Dot) Product

A vector A⃗\vec{A} of magnitude 727\sqrt{2} unit, another vector B⃗\vec{B} of magnitude 1414 unit are inclined at an angle of 60∘60^\circ. The magnitude of the scalar product (A⃗⋅B⃗)(\vec{A} \cdot \vec{B}) is [cos⁡(60)∘=12]\left[\cos(60)^\circ = \frac{1}{2}\right]

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Answer: (a)

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Q2MHT CET 2026 · 19 MAY · SHIFT 1Easy

Scalar (Dot) Product

In a vector p⃗\vec{p}, 'x' and 'y' components have magnitudes 2 units and 5 units respectively. A vector q⃗\vec{q}, along negative Y axis has magnitude of 3 units. Then p⃗⋅q⃗\vec{p} \cdot \vec{q} is

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Answer: (d)

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Q3MHT CET 2026 · 13 MAY · SHIFT 2Easy

Scalar (Dot) Product

The vector P⃗=ai^+aj^+3k^\vec{P} = a\hat{i} + a\hat{j} + 3\hat{k} and Q⃗=ai^−2j^−k^\vec{Q} = a\hat{i} - 2\hat{j} - \hat{k} are perpendicular to each other. Then positive value of 'aa' is

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Answer: (a)

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Q4MHT CET 2026 · 12 MAY · SHIFT 1Easy

Scalar (Dot) Product

If A⃗=5i^+2j^\vec{A} = 5\hat{i} + 2\hat{j} and B⃗=ai^+3j^\vec{B} = a\hat{i} + 3\hat{j} are perpendicular to each other, the value of 'a' is

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Answer: (a)

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Q5MHT CET 2026 · 20 APR · SHIFT 2Easy

Scalar (Dot) Product

If two vectors A⃗=4i^+nj^+2k^\vec{A} = 4\hat{i} + n\hat{j} + 2\hat{k} and B⃗=2i^+2j^−k^\vec{B} = 2\hat{i} + 2\hat{j} - \hat{k} are mutually perpendicular to each other then value of 'n' is

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Answer: (c)

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Q6MHT CET 2026 · 13 APR · SHIFT 1Easy

Scalar (Dot) Product

The vector sum of the two forces A⃗\vec{A} and B⃗\vec{B} is perpendicular to their vector difference. Hence forces A⃗\vec{A} and B⃗\vec{B} are

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Answer: (d)

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Q7MHT CET 2026 · 11 APR · SHIFT 2Easy

Scalar (Dot) Product

The vectors (A⃗+B⃗)(\vec{A} + \vec{B}) and (A⃗−B⃗)(\vec{A} - \vec{B}) are perpendicular to each other. This is possible under the condition

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Answer: (a)

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Q8MHT CET 2026 · 16 APR · SHIFT 2Medium

Scalar (Dot) Product

Vectors ai^+bj^+k^a\hat{i} + b\hat{j} + \hat{k} and 2i^−3j^+4k^2\hat{i} - 3\hat{j} + 4\hat{k} are perpendicular to each other when 3a+2b=73a + 2b = 7, the ratio of a to b is x/2x/2. The value of x is

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Answer: (b)

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Q9MHT CET 2026 · 13 APR · SHIFT 2Medium

Scalar (Dot) Product

Calculate the values of aa and bb if vectors ai^+bj^=n^a\hat{i} + b\hat{j} = \hat{n} and (i^+j^)(\hat{i} + \hat{j}) are perpendicular to each other

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Answer: (d)

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Q10MHT CET 2025 · 22 APR · SHIFT 2Easy

Scalar (Dot) Product

Given A⃗=(2i^−3j^+k^),B⃗=(3i^+j^−2k^)\vec{A} = (2\hat{i} - 3\hat{j} + \hat{k}), \quad \vec{B} = (3\hat{i} + \hat{j} - 2\hat{k}) and C⃗=(3i^+2j^+k^)\vec{C} = (3\hat{i} + 2\hat{j} + \hat{k}), then (A⃗+B⃗)⋅C⃗(\vec{A} + \vec{B}) \cdot \vec{C} will be

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Answer: (a)

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Q11MHT CET 2025 · 22 APR · SHIFT 2Easy

Scalar (Dot) Product

Given A⃗=(2i^−3j^+k^),B⃗=(3i^+j^−2k^)\vec{A} = (2\hat{i} - 3\hat{j} + \hat{k}), \quad \vec{B} = (3\hat{i} + \hat{j} - 2\hat{k}) and C⃗=(3i^+2j^+k^)\vec{C} = (3\hat{i} + 2\hat{j} + \hat{k}), then (A⃗+B⃗)⋅C⃗(\vec{A} + \vec{B}) \cdot \vec{C} will be

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Answer: (a)

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Q12MHT CET 2025 · 26 APR · SHIFT 2Easy

Scalar (Dot) Product

The vector sum of two forces A⃗\vec{A} and B⃗\vec{B} is perpendicular to their vector difference. Hence forces A⃗\vec{A} and B⃗\vec{B} are

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Answer: (d)

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Q13MHT CET 2025 · 5 MAY · SHIFT 2Medium

Scalar (Dot) Product

Two vectors ai^+bj^+k^a\hat{i} + b\hat{j} + \hat{k} and 2i^−3j^+4k^2\hat{i} - 3\hat{j} + 4\hat{k} are perpendicular to each other. When 3a+2b=73a + 2b = 7, the ratio of aa to bb is x2\frac{x}{2}. The value of xx is

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Answer: (c)

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Q14MHT CET 2025 · 23 APR · SHIFT 1Medium

Scalar (Dot) Product

If P⃗=bi^+6j^+k^\vec{P} = b\hat{i} + 6\hat{j} + \hat{k} and Q⃗=i^−aj^+4k^\vec{Q} = \hat{i} - a\hat{j} + 4\hat{k} are perpendicular to each other, also 3b−a=53b - a = 5. The value of aa and bb is

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Answer: (b)

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Q15JEE Main 2025 · 23 JAN · SHIFT 1Medium

Scalar (Dot) Product

Two particles are located at equal distance from origin. The position vectors of those are represented by A⃗=2i^+3nj^+2k^\vec{A} = 2\hat{i} + 3n\hat{j} + 2\hat{k} and B⃗=2i^−2j^+4pk^\vec{B} = 2\hat{i} - 2\hat{j} + 4p\hat{k}, respectively. If both the vectors are at right angle to each other, the value of n−1n^{-1} is ________.

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Answer: 3

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Q16JEE Main 2023 · 24 JAN · SHIFT 2Easy

Scalar (Dot) Product

If two vectors P⃗=i^+2mj^+mk^\vec{P} = \hat{i} + 2m\hat{j} + m\hat{k} and Q⃗=4i^−2j^+mk^\vec{Q} = 4\hat{i} - 2\hat{j} + m\hat{k} are perpendicular to each other. Then, the value of m will be:

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Answer: (d)

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Q17JEE Main 2023 · 24 JAN · SHIFT 1Medium

Scalar (Dot) Product

Vectors ai^+bj^+k^a\hat{i} + b\hat{j} + \hat{k} and 2i^−3j^+4k^2\hat{i} - 3\hat{j} + 4\hat{k} are perpendicular to each other when 3a+2b=73a + 2b = 7, the ratio of aa to bb is x2\frac{x}{2}. The value of xx is ____________.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

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Q18JEE Main 2022 · 28 JUL · SHIFT 1Easy

Scalar (Dot) Product

If the projection of 2i^+4j^−2k^2\hat{i} + 4\hat{j} - 2\hat{k} on i^+2j^+αk^\hat{i} + 2\hat{j} + \alpha\hat{k} is zero. Then, the value of α\alpha will be ___________.

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Answer: 5

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Q19JEE Main 2022 · 26 JUL · SHIFT 2Easy

Scalar (Dot) Product

If A⃗=(2i^+3j^−k^) m\vec{A} = (2\hat{i} + 3\hat{j} - \hat{k})\text{ m} and B⃗=(i^+2j^+2k^) m\vec{B} = (\hat{i} + 2\hat{j} + 2\hat{k})\text{ m}. The magnitude of component of vector A⃗\vec{A} along vector B⃗\vec{B} will be ____________ m\text{m}.

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Answer: 2

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Q20JEE Main 2021 · 22 JUL · SHIFT 2Easy

Scalar (Dot) Product

What will be the projection of vector A⃗=i^+j^+k^\vec{A} = \hat{i} + \hat{j} + \hat{k} on vector B⃗=i^+j^\vec{B} = \hat{i} + \hat{j}?

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Answer: (b)

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Q21MHT CET 2019 · 3 MAY · SHIFT 1Easy

Scalar (Dot) Product

The vectors (A+B)(\mathbf{A} + \mathbf{B}) and (A−B)(\mathbf{A} - \mathbf{B}) are at right angles to each other. This is possible under the condition

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Answer: (a)

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Q22MHT CET 2019 · 2 MAY · SHIFT 2Easy

Scalar (Dot) Product

P\mathbf{P} and Q\mathbf{Q} are two non-zero vectors inclined to each other at an angle ' θ\theta '. ' pp ' and ' qq ' are unit vectors along P\mathbf{P} and Q\mathbf{Q} respectively. The component of Q\mathbf{Q} in the direction of P\mathbf{P} will be

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Answer: (a)

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Q23JEE Main 2019 · 8 APR · SHIFT 2Difficult

Scalar (Dot) Product

Let ∣A⃗1∣=3, ∣A⃗2∣=5\left|\vec{A}_1\right| = 3, \ \left|\vec{A}_2\right| = 5 and ∣A⃗1+A⃗2∣=5\left|\vec{A}_1 + \vec{A}_2\right| = 5. The value of (2A⃗1+3A⃗2)⋅(3A⃗1−2A⃗2)\left(2\vec{A}_1 + 3\vec{A}_2\right) \cdot \left(3\vec{A}_1 - 2\vec{A}_2\right) is :-

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Answer: (a)

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Q24JEE Main 2018 · 16 APR · SHIFT 1Difficult

Scalar (Dot) Product

Let A⃗=(i^+j^)\vec{A} = (\hat{i} + \hat{j}) and, B⃗=(2i^−j^).\vec{B} = (2\hat{i} - \hat{j}). The magnitude of a coplanar vector C⃗\vec{C}such that A⃗⋅C⃗=B⃗⋅C⃗=A⃗⋅B⃗,\vec{A} \cdot \vec{C} = \vec{B} \cdot \vec{C} = \vec{A} \cdot \vec{B}, is given by:

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Answer: (b)

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