Q1 MHT CET 2026 · 15 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
The equation of a wave is y = 0.07 sin ( 12 π x − 3000 π t ) y = 0.07\sin(12\pi x - 3000\pi t) y = 0.07 sin ( 12 π x − 3000 π t ) where x x x is in metre and t t t is in second then 1 1 1 m m
(a) λ = \lambda = λ = m, v = 250 ,\ v = 250 , v = 250 (b) a = 0.07 a = 0.07 a = 0.07 m, v = 500 6 ,\ v = 500 \quad 6 , v = 500 6 s s m 1 1 1 m(c) n = 1500 n = 1500 n = 1500 Hz, v = 200 ,\ v = 200 , v = 200 (d) λ = \lambda = λ = m, v = 500 ,\ v = 500 , v = 500 s 3 3 3 sShow answer and solution
Answer: (a)
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Q2 MHT CET 2026 · 14 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of a plane progressive wave is Y = 0.025 sin ( 100 t + 0.25 x ) Y = 0.025\sin(100t + 0.25x) Y = 0.025 sin ( 100 t + 0.25 x ) . The frequency of this wave would be
(a) 50 π \frac{50}{\pi} π 50 Hz(b) 100 π \frac{100}{\pi} π 100 Hz(c) 100 100 100 Hz(d) 50 50 50 Hz π π \pi \quad \pi π π Show answer and solution
Answer: (a)
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Q3 MHT CET 2026 · 16 APR · SHIFT 1 Easy ☆
Progressive Wave Equation
The equation of wave motion is Y = 6 sin ( 12 π t − 0.02 π x + π 3 ) Y = 6\sin\left(12\pi t - 0.02\pi x + \frac{\pi}{3}\right) Y = 6 sin ( 12 π t − 0.02 π x + 3 π ) where x is in metre and time in second. The velocity of the wave is
(a) 200 200 200 m/s(b) 300 300 300 m/s(c) 400 400 400 m/s(d) 600 600 600 m/sShow answer and solution
Answer: (d)
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Q4 MHT CET 2026 · 13 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
A traveling wave is described by the equation y ( x , t ) = [ 0.05 sin ( 8 x − 4 t ) ] y(x, t) = [0.05\sin(8x - 4t)] y ( x , t ) = [ 0.05 sin ( 8 x − 4 t )] m
The velocity of the wave is [All the quantities are in SI unit]
(a) 4 4 4 ms− 1 -1 − 1 (b) 2 2 2 ms− 1 -1 − 1 (c) 0.5 0.5 0.5 ms− 1 -1 − 1 (d) 8 8 8 ms− 1 -1 − 1 Show answer and solution
Answer: (c)
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Q5 MHT CET 2026 · 11 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of a progressive wave is Y = 3 sin [ π ( t 3 − x 5 ) + π 4 ] Y = 3\sin\left[\pi\left(\frac{t}{3} - \frac{x}{5}\right) + \frac{\pi}{4}\right] Y = 3 sin [ π ( 3 t − 5 x ) + 4 π ] where X and Y are in metre and time in second. Which of the following is correct?
(a) Velocity = 1.5 1.5 1.5 m/s (b) Amplitude = 30 30 30 cm (c) Wavelength = 10 10 10 m (d) Frequency = 0.2 0.2 0.2 Hz Show answer and solution
Answer: (c)
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Q6 JEE Main 2026 · 2 APR · SHIFT 1 Easy ☆
Progressive Wave Equation
The equation of a plane progressive wave is given by y = 5 cos π ( 200 t − x 150 ) y = 5\cos\pi\left(200t - \frac{x}{150}\right) y = 5 cos π ( 200 t − 150 x ) where x x x and y y y are in cm and t t t is in second. The velocity of the wave is ________ m/s.
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Answer: (d)
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Q7 JEE Main 2026 · 5 APR · SHIFT 1 Easy ☆
Progressive Wave Equation
A transverse wave on a string is described by y = 3 sin ( 36 t + 0.018 x + π / 4 ) y = 3\sin(36t + 0.018x + \pi/4) y = 3 sin ( 36 t + 0.018 x + π /4 ) , where x , y x, y x , y are in cm and t t t in seconds. The least distance between the two successive crests in the wave is ______ cm. (Nearest integer)
( π = 3.14 ) (\pi = 3.14) ( π = 3.14 )
Numerical answer type. Work it out, then open the answer.
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Answer: 349
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Q8 MHT CET 2026 · 14 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
A wave travelling in the positive x x x -direction having displacement along y y y -direction as 1 1 1 m, wavelength 2 π 2\pi 2 π m and frequency Hz is represented by
1 π \frac{1}{\pi} π 1
(a) y = sin ( x − 2 t ) y = \sin(x - 2t) y = sin ( x − 2 t ) (b) y = sin ( 2 π x − 2 π t ) y = \sin(2\pi x - 2\pi t) y = sin ( 2 π x − 2 π t ) (c) y = sin ( 10 π x − 20 π t ) y = \sin(10\pi x - 20\pi t) y = sin ( 10 π x − 20 π t ) (d) y = sin ( 2 π x + 2 π t ) y = \sin(2\pi x + 2\pi t) y = sin ( 2 π x + 2 π t ) Show answer and solution
Answer: (a)
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Q9 MHT CET 2026 · 19 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of a progressive wave is given by y = 6 cos ( 100 t − 4 x ) y = 6\cos(100t - 4x) y = 6 cos ( 100 t − 4 x ) where y y y is in μ \mu μ m, x x x in metre and t t t in second. The ratio of the maximum particle velocity to the velocity of wave is
(a) 1.5 × 1 0 − 5 1.5 \times 10^{-5} 1.5 × 1 0 − 5 (b) 2.0 × 1 0 − 6 2.0 \times 10^{-6} 2.0 × 1 0 − 6 (c) 2.4 × 1 0 − 5 2.4 \times 10^{-5} 2.4 × 1 0 − 5 (d) 2.8 × 1 0 − 6 2.8 \times 10^{-6} 2.8 × 1 0 − 6 Show answer and solution
Answer: (c)
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Q10 MHT CET 2026 · 15 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
In a sine wave, minimum distance between 2 2 2 particles always having same speed is
(a) λ 2 \frac{\lambda}{2} 2 λ (b) λ 4 \frac{\lambda}{4} 4 λ (c) λ 3 \frac{\lambda}{3} 3 λ (d) λ \lambda λ Show answer and solution
Answer: (a)
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Q11 MHT CET 2026 · 15 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
Two points separated by 6 6 6 cm on a string has phase difference of 6 0 ∘ 60^\circ 6 0 ∘ . If frequency of oscillation is 500 500 500 Hz, the velocity of the wave in m s \frac{m}{s} s m is
(a) 200 200 200 (b) 180 180 180 (c) 100 100 100 (d) 80 80 80 Show answer and solution
Answer: (b)
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Q12 MHT CET 2026 · 13 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The path difference between two waves Y 1 = a 1 sin ( ω t − 2 π x λ ) Y_1 = a_1\sin\left(\omega t - \frac{2\pi x}{\lambda}\right) Y 1 = a 1 sin ( ω t − λ 2 π x ) and Y 2 = a 2 cos ( ω t − 2 π x λ + Φ ) Y_2 = a_2\cos\left(\omega t - \frac{2\pi x}{\lambda} + \Phi\right) Y 2 = a 2 cos ( ω t − λ 2 π x + Φ ) is
(a) λ Φ 2 π \frac{\lambda\Phi}{2\pi} 2 π λ Φ (b) λ 2 π ( Φ + π 2 ) \frac{\lambda}{2\pi}\left(\Phi + \frac{\pi}{2}\right) 2 π λ ( Φ + 2 π ) (c) λ 2 π ( Φ − π 2 ) \frac{\lambda}{2\pi}\left(\Phi - \frac{\pi}{2}\right) 2 π λ ( Φ − 2 π ) (d) 2 π Φ λ \frac{2\pi\Phi}{\lambda} λ 2 π Φ Show answer and solution
Answer: (b)
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Q13 MHT CET 2026 · 13 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
Two points on a travelling wave having frequency 500 500 500 Hz and velocity 300 300 300 m/s are 6 0 ∘ 60^\circ 6 0 ∘ out of phase, then the minimum distance between the two points is
(a) 0.2 0.2 0.2 m(b) 0.1 0.1 0.1 m(c) 0.5 0.5 0.5 m(d) 0.4 0.4 0.4 mShow answer and solution
Answer: (b)
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Q14 MHT CET 2026 · 12 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of a wave travelling on a string is Y = sin ( 20 π x + 10 π t ) Y = \sin(20\pi x + 10\pi t) Y = sin ( 20 π x + 10 π t ) , where x x x and t t t are distance and time in SI units. The minimum distance between two points having the same oscillating speed is
(a) 2.5 2.5 2.5 cm(b) 5 5 5 cm(c) 20 20 20 cm(d) 10 10 10 cmShow answer and solution
Answer: (b)
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Q15 MHT CET 2026 · 12 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
Two simple harmonic progressive waves have displacements y 1 = 5 sin ( 2 π x λ − ω t ) y_1 = 5\sin\left(\frac{2\pi x}{\lambda} - \omega t\right) y 1 = 5 sin ( λ 2 π x − ω t ) and y 2 = 5 cos ( 2 π x λ − ω t + π 6 ) y_2 = 5\cos\left(\frac{2\pi x}{\lambda} - \omega t + \frac{\pi}{6}\right) y 2 = 5 cos ( λ 2 π x − ω t + 6 π ) . The phase difference between the two waves is
(a) π 3 \frac{\pi}{3} 3 π (b) π 6 \frac{\pi}{6} 6 π (c) 2 π 3 \frac{2\pi}{3} 3 2 π (d) 3 π 2 \frac{3\pi}{2} 2 3 π Show answer and solution
Answer: (c)
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Q16 MHT CET 2026 · 20 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
Two waves are represented as
and
The path difference between two waves is
(a) λ 5 \frac{\lambda}{5} 5 λ (b) λ 4 \frac{\lambda}{4} 4 λ (c) λ 3 \frac{\lambda}{3} 3 λ (d) λ 2 \frac{\lambda}{2} 2 λ Show answer and solution
Answer: (c)
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Q17 MHT CET 2026 · 16 APR · SHIFT 1 Easy ☆
Progressive Wave Equation
A progressive wave of frequency 50 Hz is travelling with velocity 350 m/s through a medium. The change in phase at given time interval of 0.01s is
(a) π 4 \frac{\pi}{4} 4 π rad(b) π 2 \frac{\pi}{2} 2 π rad(c) π \pi π rad(d) 3 π 2 \frac{3\pi}{2} 2 3 π radShow answer and solution
Answer: (c)
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Q18 MHT CET 2026 · 15 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
A simple harmonic progressive wave is represented by y = A sin ( 120 π t + 3 x ) y = A\sin(120\pi t + 3x) y = A sin ( 120 π t + 3 x ) . The distance between two points on the wave at a phase difference of π 3 \frac{\pi}{3} 3 π radian is
(a) π 6 \frac{\pi}{6} 6 π m(b) π 9 \frac{\pi}{9} 9 π m(c) 2 π 9 \frac{2\pi}{9} 9 2 π m(d) π 18 \frac{\pi}{18} 18 π mShow answer and solution
Answer: (b)
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Q19 MHT CET 2026 · 13 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
Two waves are represented by the equations, y 1 = a sin ( ω t + k x + 0.57 ) y_1 = a\sin(\omega t + kx + 0.57) y 1 = a sin ( ω t + k x + 0.57 ) m and y 2 = a cos ( ω t + k x ) y_2 = a\cos(\omega t + kx) y 2 = a cos ( ω t + k x ) m, where x x x is in metre and t t t is in second. What is the phase difference between them? (π = 3.14 \pi = 3.14 π = 3.14 )
(a) 0.57 0.57 0.57 radian(b) 1.57 1.57 1.57 radian(c) 1.25 1.25 1.25 radian(d) 1.0 1.0 1.0 radianShow answer and solution
Answer: (d)
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Q20 MHT CET 2026 · 13 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
The distance between two consecutive points with phase difference of 6 0 ∘ 60^\circ 6 0 ∘ in a wave of frequency n n n is x x x meter. The velocity with which wave is traveling is
(a) n x nx n x (b) 2 n x 2nx 2 n x (c) 3 n x 3nx 3 n x (d) 6 n x 6nx 6 n x Show answer and solution
Answer: (d)
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Q21 NEET 2026 Easy ☆
Progressive Wave Equation
For a travelling harmonic wave
y ( x , t ) = 2.0 cos 2 π ( 10 t − 0.0080 x + 0.35 ) y(x, t) = 2.0\cos 2\pi(10t - 0.0080x + 0.35) y ( x , t ) = 2.0 cos 2 π ( 10 t − 0.0080 x + 0.35 ) , where x x x and y y y are in cm and t t t in s \text{s} s . The phase difference between oscillatory motion of two points separated by a distance of 0.5 m is:
(a) 0.08 π rad 0.08\pi\text{ rad} 0.08 π rad (b) 0.8 π rad 0.8\pi\text{ rad} 0.8 π rad (c) 8 π rad 8\pi\text{ rad} 8 π rad (d) 0.008 π rad 0.008\pi\text{ rad} 0.008 π rad Show answer and solution
Answer: (b)
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Q22 MHT CET 2026 · 12 MAY · SHIFT 1 Medium ☆
Progressive Wave Equation
A simple harmonic progressive wave is given by the equation y = a sin 2 π ( n t − x λ ) y = a\sin 2\pi\left(nt - \frac{x}{\lambda}\right) y = a sin 2 π ( n t − λ x ) . If the wave velocity is equal to 1 6 × \frac{1}{6} \times 6 1 × (maximum particle velocity), then the wavelength λ \lambda λ is { a = \{a = { a = amplitude, n = n = n = frequency, t = t = t = time, y = y = y = displacement, x = x = x = distance} \} }
(a) π a 2 \frac{\pi a}{2} 2 πa (b) π a 3 \frac{\pi a}{3} 3 πa (c) 3 π a 2 \frac{3\pi a}{2} 2 3 πa (d) 2 π a 3 \frac{2\pi a}{3} 3 2 πa Show answer and solution
Answer: (b)
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Q23 MHT CET 2026 · 15 MAY · SHIFT 1 Medium ☆
Progressive Wave Equation
A transverse wave is propagating on the string. The linear density of vibrating string is 1 0 − 3 10^{-3} 1 0 − 3 kg/m. The equation of the wave is Y = 0.05 sin ( x + 15 t ) Y = 0.05\sin(x + 15t) Y = 0.05 sin ( x + 15 t ) where x x x and Y Y Y are in metre and time in second. The tension in the string is
(a) 0.2 0.2 0.2 N(b) 0.25 0.25 0.25 N(c) 0.225 0.225 0.225 N(d) 0.325 0.325 0.325 NShow answer and solution
Answer: (c)
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Q24 MHT CET 2026 · 20 APR · SHIFT 2 Medium ☆
Progressive Wave Equation
The equation of a wave on a string of linear mass density 0.02 0.02 0.02 kg m− 1 ^{-1} − 1 is
Y = 0.01 sin [ 2 π ( t 0.02 − x 0.50 ) ] Y = 0.01\sin\left[2\pi\left(\frac{t}{0.02} - \frac{x}{0.50}\right)\right] Y = 0.01 sin [ 2 π ( 0.02 t − 0.50 x ) ] m. The tension in the string is
(a) 12.50 12.50 12.50 N(b) 6.25 6.25 6.25 N(c) 25 25 25 N(d) 50 50 50 NShow answer and solution
Answer: (a)
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Q25 MHT CET 2025 · 21 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of a progressive wave is Y = 3 sin [ π ( t 3 − x 5 ) + π 4 ] Y = 3\sin\left[\pi\left(\frac{t}{3} - \frac{x}{5}\right) + \frac{\pi}{4}\right] Y = 3 sin [ π ( 3 t − 5 x ) + 4 π ] where x and y are in meter and time in second. Which of the following is correct?
(a) Wavelength = 10 m = 10\text{ m} = 10 m (b) Velocity = 1.5 m/s = 1.5\text{ m/s} = 1.5 m/s (c) Amplitude = 3 cm = 3\text{ cm} = 3 cm (d) Frequency = 0.2 Hz = 0.2\text{ Hz} = 0.2 Hz Show answer and solution
Answer: (a)
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Q26 JEE Main 2025 · 4 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
Displacement of a wave is expressed as x ( t ) = 5 cos ( 628 t + π 2 ) m x(t) = 5\cos\left(628t + \frac{\pi}{2}\right)\text{m} x ( t ) = 5 cos ( 628 t + 2 π ) m . The wavelength of the wave when its velocity is 300 m/s 300\text{ m/s} 300 m/s is:
( π = 3.14 ) (\pi = 3.14) ( π = 3.14 )
(a) 0.33 m (b) 0.5 m (c) 3 m (d) 5 m Show answer and solution
Answer: (c)
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Q27 JEE Main 2025 · 23 JAN · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of a transverse wave travelling along a string is
y ( x , t ) = 4.0 sin [ 20 × 1 0 − 3 x + 600 t ] mm y(x, t) = 4.0\sin\left[20 \times 10^{-3}x + 600t\right]\text{mm} y ( x , t ) = 4.0 sin [ 20 × 1 0 − 3 x + 600 t ] mm , where x x x is in mm and t t t is in second. The velocity of the wave is:
(a) − 60 m/s -60\text{ m/s} − 60 m/s (b) + 60 m/s +60\text{ m/s} + 60 m/s (c) + 30 m/s +30\text{ m/s} + 30 m/s (d) − 30 m/s -30\text{ m/s} − 30 m/s Show answer and solution
Answer: (d)
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Q28 MHT CET 2025 · 23 APR · SHIFT 1 Easy ☆
Progressive Wave Equation
A particle performs S.H.M. of amplitude 'A' and wavelength ' λ \lambda λ ', Then the velocity of the wave (V) and the maximum particle velocity (v) are related as
(a) v = λ V 4 π A v = \frac{\lambda V}{4\pi A} v = 4 π A λV (b) V = λ v 4 π A V = \frac{\lambda v}{4\pi A} V = 4 π A λ v (c) v = 2 π A λ V v = \frac{2\pi A}{\lambda}V v = λ 2 π A V (d) V = 2 π A λ v V = \frac{2\pi A}{\lambda}v V = λ 2 π A v Show answer and solution
Answer: (c)
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Q29 MHT CET 2025 · 22 APR · SHIFT 1 Easy ☆
Progressive Wave Equation
The equation of wave is y = 60 sin ( 1200 t − 6 x ) y = 60\sin(1200t - 6x) y = 60 sin ( 1200 t − 6 x ) , where ' y y y ' is in micron, ' t t t ' is in second and ' x x x ' is in metre. The ratio of maximum particle velocity to the wave velocity of wave propagation is
(a) 36 (b) 3.6 × 1 0 − 5 3.6 \times 10^{-5} 3.6 × 1 0 − 5 (c) 3.6 × 1 0 − 4 3.6 \times 10^{-4} 3.6 × 1 0 − 4 (d) 3.6 × 1 0 − 6 3.6 \times 10^{-6} 3.6 × 1 0 − 6 Show answer and solution
Answer: (c)
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Q30 MHT CET 2025 · 5 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The distance between two consecutive points with phase difference of 4 5 ∘ 45^\circ 4 5 ∘ in a wave of frequency 300 Hz is 4.0 m. The velocity of the travelling wave is (in km/s \text{km/s} km/s )
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Answer: (d)
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Q31 MHT CET 2025 · 19 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
A progressive wave of frequency 400 Hz is travelling with velocity 336 m/s 336\text{ m/s} 336 m/s . How far apart are the two points on a wave which are 6 0 ∘ 60^\circ 6 0 ∘ out of phase?
(a) 0.12 m (b) 0.14 m (c) 0.21 m (d) 0.28 m Show answer and solution
Answer: (b)
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Q32 JEE Main 2025 · 7 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of a wave travelling on a string is y = sin[20πx + 10πt], where x and t are distance and time in SI units. The minimum distance between two points having the same oscillating speed is:
(a) 10 cm (b) 2.5 cm (c) 20 cm (d) 5.0 cm Show answer and solution
Answer: (d)
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Q33 JEE Main 2025 · 2 APR · SHIFT 2 Medium ☆
Progressive Wave Equation
A sinusoidal wave of wavelength 7.5 cm travels a distance of 1.2 cm along the x x x -direction in 0.3 sec. The crest P is at x = 0 x = 0 x = 0 at t = 0 sec t = 0\text{ sec} t = 0 sec and maximum displacement of the wave is 2 cm. Which equation correctly represents this wave?
(a) y = 2 cos ( 0.83 x − 3.35 t ) cm y = 2\cos(0.83x - 3.35t)\text{ cm} y = 2 cos ( 0.83 x − 3.35 t ) cm (b) y = 2 sin ( 0.83 x − 3.5 t ) cm y = 2\sin(0.83x - 3.5t)\text{ cm} y = 2 sin ( 0.83 x − 3.5 t ) cm (c) y = 2 cos ( 0.13 x − 0.5 t ) cm y = 2\cos(0.13x - 0.5t)\text{ cm} y = 2 cos ( 0.13 x − 0.5 t ) cm (d) y = 2 cos ( 3.35 x − 0.83 t ) cm y = 2\cos(3.35x - 0.83t)\text{ cm} y = 2 cos ( 3.35 x − 0.83 t ) cm Show answer and solution
Answer: (a)
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Q34 MHT CET 2025 · 21 APR · SHIFT 2 Medium ☆
Progressive Wave Equation
A transverse displacement of vibrating string is y = 0.06 sin ( 2 π 3 x ) cos ( 120 π t ) y = 0.06\sin\left(\frac{2\pi}{3}x\right)\cos(120\pi t) y = 0.06 sin ( 3 2 π x ) cos ( 120 π t ) .
If the mass per unit length of a string is 4 × 1 0 − 2 kg/m 4 \times 10^{-2}\text{ kg/m} 4 × 1 0 − 2 kg/m , then the tension in the string will be
(a) 1296 N (b) 1000 N (c) 720 N (d) 500 N Show answer and solution
Answer: (a)
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Q35 MHT CET 2024 · 15 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
A wave is given by Y = 3 sin 2 π ( t 0.04 − x 0.01 ) Y = 3\sin 2\pi\left(\frac{t}{0.04} - \frac{x}{0.01}\right) Y = 3 sin 2 π ( 0.04 t − 0.01 x ) where Y is in cm. Frequency of the wave and maximum acceleration will be ( π 2 = 10 ) (\pi^2 = 10) ( π 2 = 10 )
(a) 100 Hz , 4.7 × 1 0 4 cm/s 2 100\text{ Hz}, 4.7 \times 10^{4}\text{ cm/s}^2 100 Hz , 4.7 × 1 0 4 cm/s 2 (b) 50 Hz , 7.5 × 1 0 3 cm/s 2 50\text{ Hz}, 7.5 \times 10^{3}\text{ cm/s}^2 50 Hz , 7.5 × 1 0 3 cm/s 2 (c) 25 Hz , 4.7 × 1 0 4 cm/s 2 25\text{ Hz}, 4.7 \times 10^{4}\text{ cm/s}^2 25 Hz , 4.7 × 1 0 4 cm/s 2 (d) 25 Hz , 7.5 × 1 0 4 cm/s 2 25\text{ Hz}, 7.5 \times 10^{4}\text{ cm/s}^2 25 Hz , 7.5 × 1 0 4 cm/s 2 Show answer and solution
Answer: (d)
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Q36 NEET 2024 Easy ☆
Progressive Wave Equation
The displacement of a travelling wave y = C sin 2 π λ ( a t − x ) y = C\sin\frac{2\pi}{\lambda}(at - x) y = C sin λ 2 π ( a t − x ) where t t t is time, x x x is distance and λ \lambda λ is the wavelength, all in S.I. units. Then the frequency of the wave is
(a) 2 π λ a \frac{2\pi\lambda}{a} a 2 πλ (b) 2 π a λ \frac{2\pi a}{\lambda} λ 2 πa (c) λ a \frac{\lambda}{a} a λ (d) a λ \frac{a}{\lambda} λ a Show answer and solution
Answer: (d)
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Q37 JEE Main 2024 · 8 APR · SHIFT 2 Easy ☆
Progressive Wave Equation
A plane progressive wave is given by y = 2 cos 2 π ( 330 t − x ) m y = 2\cos 2\pi(330t - x)\text{m} y = 2 cos 2 π ( 330 t − x ) m . The frequency of the wave is:
(a) 660 Hz (b) 340 Hz (c) 330 Hz (d) 165 Hz Show answer and solution
Answer: (c)
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Q38 MHT CET 2024 · 3 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
The displacement of a wave is given by y = 0.002 sin ( 100 t + x ) y = 0.002\sin(100t + x) y = 0.002 sin ( 100 t + x ) where ' x x x 'and ' y y y ' are in metre and ' t t t ' is in second. This represents a wave
(a) of wavelength one metre (b) travelling with a velocity of 100 m/s 100\text{ m/s} 100 m/s in the negative x x x -direction (c) of frequency ( 100 π ) Hz \left(\frac{100}{\pi}\right)\text{ Hz} ( π 100 ) Hz (d) travelling with a velocity of ( 50 π ) m/s \left(\frac{50}{\pi}\right)\text{m/s} ( π 50 ) m/s in the positive x -direction Show answer and solution
Answer: (b)
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Q39 MHT CET 2024 · 15 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
Velocity of sound waves in air is 330 m/s 330\text{ m/s} 330 m/s . For a particular sound wave in air, path difference of 40 cm is equivalent to phase difference of 1.6 π 1.6\pi 1.6 π . frequency of this wave is
(a) 165 Hz (b) 150 Hz (c) 660 Hz (d) 330 Hz Show answer and solution
Answer: (c)
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Q40 MHT CET 2024 · 9 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The diagram shows the propagation of a progressive wave. A, B, C, D, E are five points on this wave
Which of the following points are in the same state of vibration?
(a) A, B (b) B, C (c) B, D (d) E, B Show answer and solution
Answer: (d)
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Q41 MHT CET 2024 · 4 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
A transverse wave travelling along a stretched string has a speed of 30 m/s 30\text{ m/s} 30 m/s and a frequency of 250 Hz. The phase difference between two points on the string 10 cm apart at the same instant is
(a) 0 c 0^{c} 0 c (b) ( π 2 ) c \left(\frac{\pi}{2}\right)^{c} ( 2 π ) c (c) ( 5 π 3 ) c \left(\frac{5\pi}{3}\right)^{c} ( 3 5 π ) c (d) ( 8 π 3 ) c \left(\frac{8\pi}{3}\right)^{c} ( 3 8 π ) c Show answer and solution
Answer: (c)
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Q42 MHT CET 2024 · 4 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
The distance between two consecutive points with phase difference of 6 0 ∘ 60^\circ 6 0 ∘ in wave of frequency 500 Hz is 0.6 m. The velocity with which wave is travelling is
(a) 1.8 km/s 1.8\text{ km/s} 1.8 km/s (b) 9 km/s 9\text{ km/s} 9 km/s (c) 3.6 km/s 3.6\text{ km/s} 3.6 km/s (d) 2.7 km/s 2.7\text{ km/s} 2.7 km/s Show answer and solution
Answer: (a)
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Q43 MHT CET 2024 · 4 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
A progressive wave of frequency 400 Hz is travelling with a velocity 336 m/s 336\text{ m/s} 336 m/s . How far apart are the two points which are 6 0 ∘ 60^\circ 6 0 ∘ out of phase?
(a) 0.14 m (b) 0.21 m (c) 0.24 m (d) 0.28 m Show answer and solution
Answer: (a)
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Q44 MHT CET 2024 · 3 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
The path difference between two waves Y 1 = a 1 sin ( ω t − 2 π x λ ) Y_1 = a_1\sin\left(\omega t - \frac{2\pi x}{\lambda}\right) Y 1 = a 1 sin ( ω t − λ 2 π x ) and Y 2 = a 2 cos ( ω t − 2 π x λ + ϕ ) Y_2 = a_2\cos\left(\omega t - \frac{2\pi x}{\lambda} + \phi\right) Y 2 = a 2 cos ( ω t − λ 2 π x + ϕ ) is
(a) λ ϕ 2 π \frac{\lambda\phi}{2\pi} 2 π λ ϕ (b) λ 2 π ( ϕ + π 2 ) \frac{\lambda}{2\pi}\left(\phi + \frac{\pi}{2}\right) 2 π λ ( ϕ + 2 π ) (c) 2 π λ ( ϕ − π 2 ) \frac{2\pi}{\lambda}\left(\phi - \frac{\pi}{2}\right) λ 2 π ( ϕ − 2 π ) (d) 2 π λ ϕ \frac{2\pi}{\lambda}\phi λ 2 π ϕ Show answer and solution
Answer: (b)
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Q45 MHT CET 2024 · 2 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
Two simple harmonic progressive waves have displacements y 1 = a 1 sin ( 2 π x λ − ω t ) y_1 = a_1\sin\left(\frac{2\pi x}{\lambda} - \omega t\right) y 1 = a 1 sin ( λ 2 π x − ω t ) and y 2 = a 2 cos ( 2 π x λ − ω t + ϕ ) y_2 = a_2\cos\left(\frac{2\pi x}{\lambda} - \omega t + \phi\right) y 2 = a 2 cos ( λ 2 π x − ω t + ϕ ) What is the phase difference between two waves?
(a) ( ϕ + π 2 ) \left(\phi + \frac{\pi}{2}\right) ( ϕ + 2 π ) (b) ϕ \phi ϕ (c) ( ϕ − π 2 ) \left(\phi - \frac{\pi}{2}\right) ( ϕ − 2 π ) (d) ( ϕ + π ) (\phi + \pi) ( ϕ + π ) Show answer and solution
Answer: (a)
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Q46 MHT CET 2024 · 2 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
Velocity of sound waves in air is 330 m/s 330\text{ m/s} 330 m/s . For a particular sound wave in air, path difference of 40 cm is equivalent to phase difference of 1.6 π 1.6\pi 1.6 π . The frequency of this wave is
(a) 165 Hz (b) 150 Hz (c) 660 Hz (d) 330 Hz Show answer and solution
Answer: (c)
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Q47 MHT CET 2024 · 15 MAY · SHIFT 2 Medium ☆
Progressive Wave Equation
A string has mass per unit length of 1 0 − 6 kg/cm 10^{-6}\text{ kg/cm} 1 0 − 6 kg/cm The equation of simple harmonic wave produced in it is Y = 0.2 sin ( 2 x + 80 t ) m Y = 0.2\sin(2x + 80t)\text{ m} Y = 0.2 sin ( 2 x + 80 t ) m . The tension in the string is
(a) 0.16 N (b) 0.0016 N (c) 1.6 N 1.6\text{ N} 1.6 N (d) 16 N Show answer and solution
Answer: (a)
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Q48 MHT CET 2023 · 12 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of wave motion is Y = 5 sin ( 10 π t − 0.02 π x + π / 3 ) Y = 5\sin(10\pi t - 0.02\pi x + \pi/3) Y = 5 sin ( 10 π t − 0.02 π x + π /3 ) where x x x is in metre and t t t in second. The velocity of the wave is
(a) 300 m/s (b) 400 m/s (c) 500 m/s (d) 600 m/s Show answer and solution
Answer: (c)
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Q49 MHT CET 2023 · 10 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of wave is Y = 6 sin ( 12 π t − 0.02 π x + π 3 ) Y = 6\sin\left(12\pi t - 0.02\pi x + \frac{\pi}{3}\right) Y = 6 sin ( 12 π t − 0.02 π x + 3 π ) where 'x x x ' is in m \text{m} m and 't t t ' in s \text{s} s . The velocity of the wave is
(a) 200 m/s 200\text{ m/s} 200 m/s (b) 300 m/s 300\text{ m/s} 300 m/s (c) 400 m/s 400\text{ m/s} 400 m/s (d) 600 m/s 600\text{ m/s} 600 m/s Show answer and solution
Answer: (d)
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Q50 JEE Main 2023 · 24 JAN · SHIFT 1 Easy ☆
Progressive Wave Equation
A travelling wave is described by the equation
y ( x , t ) = [ 0.05 sin ( 8 x − 4 t ) ] y(x, t) = [0.05\sin(8x - 4t)] y ( x , t ) = [ 0.05 sin ( 8 x − 4 t )] m
The velocity of the wave is: [all the quantities are in SI unit]
(a) 4 ms − 1 4\text{ ms}^{-1} 4 ms − 1 (b) 2 ms − 1 2\text{ ms}^{-1} 2 ms − 1 (c) 8 ms − 1 8\text{ ms}^{-1} 8 ms − 1 (d) 0.5 ms − 1 0.5\text{ ms}^{-1} 0.5 ms − 1 Show answer and solution
Answer: (d)
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Q51 JEE Main 2023 · 11 APR · SHIFT 1 Easy ☆
Progressive Wave Equation
The equation of wave is given by
Y = 1 0 − 2 sin 2 π ( 160 t − 0.5 x + π / 4 ) Y = 10^{-2}\sin 2\pi(160t - 0.5x + \pi/4) Y = 1 0 − 2 sin 2 π ( 160 t − 0.5 x + π /4 )
where x x x and Y Y Y are in m \text{m} m and t t t in s \text{s} s . The speed of the wave is ________ km h − 1 \text{km h}^{-1} km h − 1 .
Numerical answer type. Work it out, then open the answer.
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Answer: 1152
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Q52 JEE Main 2023 · 10 APR · SHIFT 1 Easy ☆
Progressive Wave Equation
A transverse harmonic wave on a string is given by
y ( x , t ) = 5 sin ( 6 t + 0.003 x ) y(x, t) = 5\sin(6t + 0.003x) y ( x , t ) = 5 sin ( 6 t + 0.003 x )
where x and y are in cm and t in sec. The wave velocity is _______________ ms− 1 -1 − 1 .
Numerical answer type. Work it out, then open the answer.
Show answer and solution
Answer: 20
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Q53 MHT CET 2023 · 13 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The equation of a progressive wave is Y = a sin 2 π ( n t − x 5 ) Y = a\sin 2\pi\left(nt - \frac{x}{5}\right) Y = a sin 2 π ( n t − 5 x ) . The ratio of maximum particle velocity to wave velocity is
(a) π a 5 \frac{\pi a}{5} 5 πa (b) 2 π a 5 \frac{2\pi a}{5} 5 2 πa (c) 3 π a 5 \frac{3\pi a}{5} 5 3 πa (d) 4 π a 5 \frac{4\pi a}{5} 5 4 πa Show answer and solution
Answer: (b)
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Q54 MHT CET 2023 · 14 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
A progressive wave is given by, Y = 12 sin ( 5 t − 4 x ) Y = 12\sin(5t - 4x) Y = 12 sin ( 5 t − 4 x ) . On this wave, how far away are the two points having a phase difference of 9 0 ∘ 90^\circ 9 0 ∘ ?
(a) π 4 \frac{\pi}{4} 4 π (b) π 8 \frac{\pi}{8} 8 π (c) π 16 \frac{\pi}{16} 16 π (d) π 32 \frac{\pi}{32} 32 π Show answer and solution
Answer: (b)
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Q55 MHT CET 2023 · 12 MAY · SHIFT 1 Easy ☆
Progressive Wave Equation
The displacement of two sinusoidal waves is given by the equation
y 1 = 8 sin ( 20 x − 30 t ) y 2 = 8 sin ( 25 x − 40 t ) \begin{matrix} y_1 = 8\sin(20x - 30t) \\ y_2 = 8\sin(25x - 40t) \end{matrix} y 1 = 8 sin ( 20 x − 30 t ) y 2 = 8 sin ( 25 x − 40 t )
then the phase difference between the waves after time t = 2 s t = 2\text{ s} t = 2 s and distance x = 5 cm x = 5\text{ cm} x = 5 cm will be
(a) 2 radian (b) 3 radian (c) 4 radian (d) 5 radian Show answer and solution
Answer: (d)
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Q56 MHT CET 2023 · 11 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
The path difference between two waves, represented by y 1 = a 1 sin ( ω t − 2 π x λ ) y_1 = a_1\sin\left(\omega t - \frac{2\pi x}{\lambda}\right) y 1 = a 1 sin ( ω t − λ 2 π x ) and y 2 = a 2 cos ( ω t − 2 π x λ + ϕ ) y_2 = a_2\cos\left(\omega t - \frac{2\pi x}{\lambda} + \phi\right) y 2 = a 2 cos ( ω t − λ 2 π x + ϕ ) is
(a) λ 2 π ( ϕ ) \frac{\lambda}{2\pi}(\phi) 2 π λ ( ϕ ) (b) λ 2 π ( ϕ + π 2 ) \frac{\lambda}{2\pi}\left(\phi + \frac{\pi}{2}\right) 2 π λ ( ϕ + 2 π ) (c) 2 π λ ( ϕ − π 2 ) \frac{2\pi}{\lambda}\left(\phi - \frac{\pi}{2}\right) λ 2 π ( ϕ − 2 π ) (d) 2 π λ ( ϕ ) \frac{2\pi}{\lambda}(\phi) λ 2 π ( ϕ ) Show answer and solution
Answer: (b)
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Q57 JEE Main 2023 · 25 JAN · SHIFT 1 Easy ☆
Progressive Wave Equation
The distance between two consecutive points with phase difference of 60∘ ^\circ ∘ in a wave of frequency 500 Hz is 6.0 m. The velocity with which wave is travelling is __________ km/s
Numerical answer type. Work it out, then open the answer.
Show answer and solution
Answer: 18
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Q58 MHT CET 2023 · 11 MAY · SHIFT 1 Medium ☆
Progressive Wave Equation
A transverse wave Y = 2 sin ( 0.01 x + 30 t ) Y = 2\sin(0.01x + 30t) Y = 2 sin ( 0.01 x + 30 t ) moves on a stretched string from one end to another end in 0.5 second. If x x x and y y y are in cm \text{cm} cm and t t t in second, then the length of the string is
(a) 5 m (b) 10 m (c) 15 m (d) 20 m Show answer and solution
Answer: (c)
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Q59 MHT CET 2023 · 11 MAY · SHIFT 2 Medium ☆
Progressive Wave Equation
A transverse wave in a medium is given by y = A sin 2 ( ω t − k x ) y = A\sin 2(\omega t - kx) y = A sin 2 ( ω t − k x ) . It is found that the magnitude of the maximum velocity of particles in the medium is equal to that of the wave velocity. What is the value of A A A ?
(a) 2 λ π \frac{2\lambda}{\pi} π 2 λ (b) λ π \frac{\lambda}{\pi} π λ (c) λ 2 π \frac{\lambda}{2\pi} 2 π λ (d) λ 4 π \frac{\lambda}{4\pi} 4 π λ Show answer and solution
Answer: (d)
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Q60 MHT CET 2023 · 9 MAY · SHIFT 2 Medium ☆
Progressive Wave Equation
The equation of simple harmonic progressive wave is given by y = a sin 2 π ( b t − c x ) y = a\sin 2\pi(bt - cx) y = a sin 2 π ( b t − c x ) . The maximum particle velocity will be half the wave velocity, if c = c = c =
(a) 2 π a 2\pi a 2 πa (b) 1 4 π a \frac{1}{4\pi a} 4 πa 1 (c) 1 2 π a \frac{1}{2\pi a} 2 πa 1 (d) 4 π a 4\pi a 4 πa Show answer and solution
Answer: (b)
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Q61 MHT CET 2023 · 14 MAY · SHIFT 1 Medium ☆
Progressive Wave Equation
The equation of the wave is Y = 10 sin ( 2 π t 30 + α ) Y = 10\sin\left(\frac{2\pi t}{30} + \alpha\right) Y = 10 sin ( 30 2 π t + α ) If the displacement is 5 cm 5\text{ cm} 5 cm at t = 0 t = 0 t = 0 then the total phase at t = 7.5 s t = 7.5\text{ s} t = 7.5 s will be ( sin 3 0 ∘ = 0.5 ) (\sin 30^\circ = 0.5) ( sin 3 0 ∘ = 0.5 )
(a) π 3 rad \frac{\pi}{3}\text{ rad} 3 π rad (b) π 2 rad \frac{\pi}{2}\text{ rad} 2 π rad (c) 2 π 5 rad \frac{2\pi}{5}\text{ rad} 5 2 π rad (d) 2 π 3 rad \frac{2\pi}{3}\text{ rad} 3 2 π rad Show answer and solution
Answer: (d)
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Q62 JEE Main 2022 · 28 JUL · SHIFT 1 Easy ☆
Progressive Wave Equation
In the wave equation
y = 0.5 sin 2 π λ ( 400 t − x ) m y = 0.5\sin\frac{2\pi}{\lambda}(400t - x)\text{ m} y = 0.5 sin λ 2 π ( 400 t − x ) m
the velocity of the wave will be:
(a) 200 m/s (b) 2002 \sqrt{2} 2 m/s (c) 400 m/s (d) 4002 \sqrt{2} 2 m/s Show answer and solution
Answer: (c)
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Q63 JEE Main 2022 · 30 JUN · SHIFT 1 Easy ☆
Progressive Wave Equation
Which of the following equations correctly represents a travelling wave having wavelength λ \lambda λ = 4.0 cm, frequency ν \nu ν = 100 Hz and travelling in positive x-axis direction?
(a) y = A sin [ ( 0.50 π cm − 1 ) x − ( 100 π s − 1 ) t ] y = A\sin[(0.50\pi\text{ cm}^{-1})x - (100\pi\text{ s}^{-1})t] y = A sin [( 0.50 π cm − 1 ) x − ( 100 π s − 1 ) t ] (b) y = A sin 2 π [ ( 0.25 cm − 1 ) x − ( 50 s − 1 ) t ] y = A\sin 2\pi[(0.25\text{ cm}^{-1})x - (50\text{ s}^{-1})t] y = A sin 2 π [( 0.25 cm − 1 ) x − ( 50 s − 1 ) t ] (c) y = A sin [ ( 2 π 4 cm − 1 ) x − ( 2 π 100 s − 1 ) t ] y = A\sin\left[\left(\frac{2\pi}{4}\text{ cm}^{-1}\right)x - \left(\frac{2\pi}{100}\text{ s}^{-1}\right)t\right] y = A sin [ ( 4 2 π cm − 1 ) x − ( 100 2 π s − 1 ) t ] (d) y = A sin π [ ( 0.5 cm − 1 ) x − ( 200 s − 1 ) t ] y = A\sin\pi[(0.5\text{ cm}^{-1})x - (200\text{ s}^{-1})t] y = A sin π [( 0.5 cm − 1 ) x − ( 200 s − 1 ) t ] Show answer and solution
Answer: (d)
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Q64 JEE Main 2022 · 26 JUL · SHIFT 2 Medium ☆
Progressive Wave Equation
A transverse wave is represented by y = 2 sin ( ω t − k x ) cm y = 2\sin(\omega t - kx)\text{ cm} y = 2 sin ( ω t − k x ) cm . The value of wavelength (in cm \text{cm} cm ) for which the wave velocity becomes equal to the maximum particle velocity, will be:
(a) 4π \pi π (b) 2π \pi π (c) π \pi π (d) 2 Show answer and solution
Answer: (a)
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Q65 JEE Main 2022 · 29 JUN · SHIFT 1 Medium ☆
Progressive Wave Equation
A longitudinal wave is represented by x = 10 sin 2 π ( n t − x λ ) x = 10\sin 2\pi\left(nt - \frac{x}{\lambda}\right) x = 10 sin 2 π ( n t − λ x ) cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to:
(a) 2π \pi π (b) 5π \pi π (c) π \pi π (d) 5 π 2 \frac{5\pi}{2} 2 5 π Show answer and solution
Answer: (b)
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Q66 MHT CET 2021 · 21 SEP · SHIFT 2 Easy ☆
Progressive Wave Equation
Equation of two simple harmonic waves are given by Y 1 = 2 sin 8 π ( t 0.2 − x 2 ) m Y_1 = 2\sin 8\pi\left(\frac{t}{0.2} - \frac{x}{2}\right)\text{m} Y 1 = 2 sin 8 π ( 0.2 t − 2 x ) m and Y 2 = 4 sin 8 π ( t 0.16 − x 1.6 ) m Y_2 = 4\sin 8\pi\left(\frac{t}{0.16} - \frac{x}{1.6}\right)\text{m} Y 2 = 4 sin 8 π ( 0.16 t − 1.6 x ) m then both waves have
(a) same period (b) same frequency (c) same wavelength (d) same velocity Show answer and solution
Answer: (d)
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Q67 JEE Main 2021 · 24 FEB · SHIFT 2 Easy ☆
Progressive Wave Equation
Which of the following equations represents a travelling wave?
(a) y = Aexcos(ω \omega ω t − θ -\theta − θ ) (b) y = Ae− - − x2(vt + θ \theta θ ) (c) y = A sin (15x − - − 2t) (d) y = A sinx cosω \omega ω t Show answer and solution
Answer: (c)
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Q68 MHT CET 2021 · 24 SEP · SHIFT 2 Easy ☆
Progressive Wave Equation
Velocity of sound waves in air is 'V V V ' m/s \text{m/s} m/s . For a particular sound wave in air, path difference of 'x' cm \text{cm} cm is equivalent to phase difference n π n\pi nπ . The frequency of this wave is
(a) V n x \frac{Vn}{x} x Vn (b) V n x \frac{V}{nx} n x V (c) V n 2 x \frac{Vn}{2x} 2 x Vn (d) 2 x V \frac{2x}{V} V 2 x Show answer and solution
Answer: (c)
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Q69 MHT CET 2021 · 23 SEP · SHIFT 1 Easy ☆
Progressive Wave Equation
Two waves are represented by the equation, y 1 = A sin ( ω t + k x + 0.57 ) m y_1 = A\sin(\omega t + kx + 0.57)\text{m} y 1 = A sin ( ω t + k x + 0.57 ) m and y 2 = A cos ( ω t + k x ) m y_2 = A\cos(\omega t + kx)\text{m} y 2 = A cos ( ω t + k x ) m , where x x x is in metre and t t t is in second. What is the phase difference between them?
(a) 0.57 radian (b) 1.0 radian (c) 1.57 radian (d) 1.25 radian Show answer and solution
Answer: (b)
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Q70 MHT CET 2021 · 22 SEP · SHIFT 2 Easy ☆
Progressive Wave Equation
A sound wave of frequency 160 Hz 160\text{ Hz} 160 Hz has a velocity of 320 m/s 320\text{ m/s} 320 m/s . When it travels through air, the particles having a phase difference of 9 0 ∘ 90^\circ 9 0 ∘ , are separated by a distance of
(a) 50 cm (b) 1 cm (c) 25 cm (d) 75 cm Show answer and solution
Answer: (a)
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Q71 MHT CET 2021 · 22 SEP · SHIFT 1 Easy ☆
Progressive Wave Equation
A sound wave is travelling with a frequency of 50 Hz 50\text{ Hz} 50 Hz . The phase difference between the two points in the path of a wave is π 3 \frac{\pi}{3} 3 π . The distance between those two points is (Velocity of sound in air = 330 m/s = 330\text{ m/s} = 330 m/s )
(a) 1.1 m (b) 0.6 m (c) 2.2 m (d) 1.7 m Show answer and solution
Answer: (a)
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Q72 MHT CET 2021 · 21 SEP · SHIFT 1 Easy ☆
Progressive Wave Equation
A progressive wave of frequency 50 Hz is travelling with velocity 350 m/s through a medium. The change in phase at a given time interval of 0.01 second is
(a) π 4 \frac{\pi}{4} 4 π rad(b) 3 π 2 \frac{3\pi}{2} 2 3 π rad(c) π \pi π rad(d) π 2 \frac{\pi}{2} 2 π radShow answer and solution
Answer: (c)
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Q73 MHT CET 2021 · 22 SEP · SHIFT 1 Medium ☆
Progressive Wave Equation
A transverse wave given by y = 2 sin ( 0.01 x + 30 t ) y = 2\sin(0.01x + 30t) y = 2 sin ( 0.01 x + 30 t ) moves on a stretched string from one end to another end in 0.5 second. If 'x x x ' and 'y y y ' are in cm \text{cm} cm and 't t t ' is in second, then the length of the string is
(a) 6 m (b) 9 m (c) 12 m (d) 15 m Show answer and solution
Answer: (d)
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Q74 JEE Main 2021 · 17 MAR · SHIFT 2 Medium ☆
Progressive Wave Equation
A sound wave of frequency 245 Hz travels with the speed of 300 ms− 1 {}^{-1} − 1 along the positive x-axis. Each point of the wave moves to and fro through a total distance of 6 cm. What will be the mathematical expression of this travelling wave?
(a) Y(x, t) = 0.03 [ sin 5.1x − - − (0.2 × \times × 103)t ] (b) Y(x, t) = 0.03 [ sin 5.1x − - − (1.5 × \times × 103)t ] (c) Y(x, t) = 0.06 [ sin 5.1x − - − (1.5 × \times × 103)t ] (d) Y(x, t) = 0.06 [ sin 0.8x − - − (0.5 × \times × 103)t ] Show answer and solution
Answer: (b)
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Q75 MHT CET 2021 · 21 SEP · SHIFT 1 Medium ☆
Progressive Wave Equation
A simple harmonic progressive wave is given by Y = Y 0 sin 2 π ( n t − x λ ) Y = Y_0\sin 2\pi\left(nt - \frac{x}{\lambda}\right) Y = Y 0 sin 2 π ( n t − λ x ) . If the wave velocity is ( 1 8 ) \left(\frac{1}{8}\right) ( 8 1 ) th the maximum particle velocity then the wavelength is
(a) π Y 0 2 \frac{\pi Y_0}{2} 2 π Y 0 (b) π Y 0 4 \frac{\pi Y_0}{4} 4 π Y 0 (c) π Y 0 8 \frac{\pi Y_0}{8} 8 π Y 0 (d) π Y 0 16 \frac{\pi Y_0}{16} 16 π Y 0 Show answer and solution
Answer: (b)
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Q76 MHT CET 2021 · 20 SEP · SHIFT 1 Medium ☆
Progressive Wave Equation
The equation of wave is given by y = 10 sin ( 2 π t 30 + α ) y = 10\sin\left(\frac{2\pi t}{30} + \alpha\right) y = 10 sin ( 30 2 π t + α ) . If the displacement is 5 cm 5\text{ cm} 5 cm at t = 0 t = 0 t = 0 , then the total phase at t = 7.5 s t = 7.5\text{ s} t = 7.5 s will be
[ sin 3 0 ∘ = cos 6 0 ∘ = 1 2 , cos 3 0 ∘ = sin 6 0 ∘ = 3 2 ] \left[\sin 30^\circ = \cos 60^\circ = \frac{1}{2}, \cos 30^\circ = \sin 60^\circ = \frac{\sqrt{3}}{2}\right] [ sin 3 0 ∘ = cos 6 0 ∘ = 2 1 , cos 3 0 ∘ = sin 6 0 ∘ = 2 3 ]
(a) π 3 rad \frac{\pi}{3}\text{ rad} 3 π rad (b) π 2 rad \frac{\pi}{2}\text{ rad} 2 π rad (c) 2 π 5 rad \frac{2\pi}{5}\text{ rad} 5 2 π rad (d) 2 π 3 rad \frac{2\pi}{3}\text{ rad} 3 2 π rad Show answer and solution
Answer: (d)
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Q77 MHT CET 2021 · 21 SEP · SHIFT 2 Medium ☆
Progressive Wave Equation
The equation of simple harmonic wave produced in the string under tension 0.4 N 0.4\text{ N} 0.4 N is given by y = 4 sin ( 3 x + 60 t ) m y = 4\sin(3x + 60t)\text{ m} y = 4 sin ( 3 x + 60 t ) m . The mass per unit length of the string is
(a) 1 0 − 3 kg m − 1 10^{-3}\text{ kg m}^{-1} 1 0 − 3 kg m − 1 (b) 1 0 − 5 kg m − 1 10^{-5}\text{ kg m}^{-1} 1 0 − 5 kg m − 1 (c) 1 0 − 3 g cm − 1 10^{-3}\text{ g cm}^{-1} 1 0 − 3 g cm − 1 (d) 1 0 − 5 g cm − 1 10^{-5}\text{ g cm}^{-1} 1 0 − 5 g cm − 1 Show answer and solution
Answer: (a)
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Q78 JEE Main 2021 · 26 FEB · SHIFT 1 Medium ☆
Progressive Wave Equation
The mass per unit length of a uniform wire is 0.135 g/cm. A transverse wave of the form y = − - − 0.21 sin (x + 30t) is produced in it, where x is in meter and t is in second. Then, the expected value of tension in the wire is x × \times × 10− - − 2 N. Value of x is _________. (Round off to the nearest integer)
Numerical answer type. Work it out, then open the answer.
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Answer: 1215
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Q79 JEE Main 2021 · 20 JUL · SHIFT 1 Difficult ☆
Progressive Wave Equation
The amplitude of wave disturbance propagating in the positive x-direction is given by y = 1 1 + x 2 y = \frac{1}{1 + x^2} y = 1 + x 2 1 at time t = 0 and y = 1 1 + ( x − 2 ) 2 y = \frac{1}{1 + (x - 2)^2} y = 1 + ( x − 2 ) 2 1 at t = 1 s, where x and y are in metres. The shape of wave does not change during the propagation. The velocity of the wave will be ___________ m/s.
Numerical answer type. Work it out, then open the answer.
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Answer: 2
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Q80 JEE Main 2019 · 12 JAN · SHIFT 1 Easy ☆
Progressive Wave Equation
A travelling harmonic wave is represented by the equation y(x,t) = 10–3sin (50t + 2x), where, x and y are in metre and t is in seconds. Which of the following is a correct statement about the wave?
(a) The wave is propagating along the positive x-axis with speed 100 ms–1 (b) The wave is propagating along the positive x-axis with speed 25 ms–1 (c) The wave is propagating along the negative x-axis with speed 25 ms–1 (d) The wave is propagating along the negative x-axis with speed 100 ms–1 Show answer and solution
Answer: (c)
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Q81 MHT CET 2019 · 2 MAY · SHIFT 2 Easy ☆
Progressive Wave Equation
A simple harmonic progressive wave is represented as y = 0.03 sin π ( 2 t − 0.01 x ) m y = 0.03\sin\pi(2t - 0.01x)\text{m} y = 0.03 sin π ( 2 t − 0.01 x ) m . At a given instant of time, the phase difference between two particles 25 m apart is
(a) π rad \pi\text{ rad} π rad (b) π 2 rad \frac{\pi}{2}\text{ rad} 2 π rad (c) π 4 rad \frac{\pi}{4}\text{ rad} 4 π rad (d) π 8 rad \frac{\pi}{8}\text{ rad} 8 π rad Show answer and solution
Answer: (c)
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Q82 MHT CET 2019 · 2 MAY · SHIFT 1 Medium ☆
Progressive Wave Equation
The equation of simple harmonic progressive wave is given by Y = a sin 2 π ( b t − c x ) Y = a\sin 2\pi(bt - cx) Y = a sin 2 π ( b t − c x ) . The maximum particle velocity will be twice the wave velocity if
(a) c = π a c = \pi a c = πa (b) c = 1 2 π a c = \frac{1}{2\pi a} c = 2 πa 1 (c) c = 1 π a c = \frac{1}{\pi a} c = πa 1 (d) c = 2 π a c = 2\pi a c = 2 πa Show answer and solution
Answer: (c)
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Q83 MHT CET 2019 · 2 MAY · SHIFT 1 Medium ☆
Progressive Wave Equation
A transverse wave is propagating on the string. The linear density of a vibrating string is 1 0 − 3 kg/m 10^{-3}\text{ kg/m} 1 0 − 3 kg/m . The equation of the wave is Y = 0.05 sin ( x + 15 t ) Y = 0.05\sin(x + 15t) Y = 0.05 sin ( x + 15 t ) where x x x and Y Y Y are measured in metre and time in second. The tension force in the string is
(a) 0.2 N (b) 0.250 N (c) 0.225 N (d) 0.325 N Show answer and solution
Answer: (c)
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Q84 JEE Main 2019 · 11 JAN · SHIFT 1 Medium ☆
Progressive Wave Equation
Equation of travelling wave on a stretched string of linear density 5 g/m is y = 0.03 sin(450 t – 9x) where distance and time are measured in SI units. The tension in the string is:
(a) 10 N (b) 7.5 N (c) 5 N (d) 12.5 N Show answer and solution
Answer: (d)
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Q85 JEE Main 2019 · 12 APR · SHIFT 1 Difficult ☆
Progressive Wave Equation
A progressive wave travelling along the positive x-direction is represented by y(x,t) = Asin(kx – ω \omega ω t + ϕ \phi ϕ ). Its snapshot at t = 0 is given in the figure.
For this wave, the phase ϕ \phi ϕ is:
(a) π 2 \frac{\pi}{2} 2 π (b) π \pi π (c) 0 (d) − π 2 -\frac{\pi}{2} − 2 π Show answer and solution
Answer: (b)
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Q86 JEE Main 2014 · 9 APR · SHIFT 1 Medium ☆
Progressive Wave Equation
A transverse wave is represented by:
y = 10 π \frac{10}{\pi} π 10 sin ( 2 π T t − 2 π λ x ) \left(\frac{2\pi}{T}t - \frac{2\pi}{\lambda}x\right) ( T 2 π t − λ 2 π x )
For what value of the wavelength the wave velocity is twice the maximum particle velocity?
(a) 40 cm (b) 20 cm (c) 10 cm (d) 60 cm Show answer and solution
Answer: (a)
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Q87 NEET 2013 Easy ☆
Progressive Wave Equation
A wave travelling in the + ve x-direction having displacement along y-direction as 1 m, wavelength 2π \pi π m and frequency of 1 π \frac{1}{\pi} π 1 Hz is represented by
(a) y = sin(10π \pi π x − - − 20π \pi π t) (b) y = sin(2π \pi π x + 2π \pi π t) (c) y = sin(x − - − 2t) (d) y = = = sin(2π \pi π x − - − 2π \pi π t) Show answer and solution
Answer: (c)
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Q88 NEET 2012 · AIPMT · MAINS Easy ☆
Progressive Wave Equation
The equation of a simple harmonic wave is given by
y = 3 sinπ 2 \frac{\pi}{2} 2 π (50t − - − x),
where x and y are in metres and t is in seconds. The ratio of maximum particle velocity to the wave velocity is
(a) 2π \pi π (b) 3 π 2 \frac{3\pi}{2} 2 3 π (c) 3 π 3\pi 3 π (d) 2 π 3 \frac{2\pi}{3} 3 2 π Show answer and solution
Answer: (b)
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Q89 JEE Main 2011 · AIEEE Easy ☆
Progressive Wave Equation
The transverse displacement y ( x , t ) y(x, t) y ( x , t ) of a wave on a string is given by y ( x , t ) = e − ( a x 2 + b t 2 + 2 a b x t ) . y(x, t) = e^{-\left(ax^2 + bt^2 + 2\sqrt{ab}\,xt\right)}. y ( x , t ) = e − ( a x 2 + b t 2 + 2 ab x t ) . This represents a:
(a) wave moving in − x -x − x direction with speed b a \sqrt{\frac{b}{a}} a b (b) standing wave of frequency b \sqrt{b} b (c) standing wave of frequency 1 b \frac{1}{\sqrt{b}} b 1 (d) wave moving in + x +x + x direction with speed a b \sqrt{\frac{a}{b}} b a Show answer and solution
Answer: (a)
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Q90 NEET 2011 · AIPMT · PRELIMS Easy ☆
Progressive Wave Equation
Two waves are represented by the equations
y1 = a a a sin(ω \omega ω t + kx + 0.57) m and
y2 = acos(ω \omega ω t + kx) m, where x is in meter and t in \text{in} in sec. The phase difference between them is
(a) 1.0 radian (b) 1.25 radian (c) 1.57 radian (d) 0.57 radian Show answer and solution
Answer: (a)
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Q91 NEET 2010 · AIPMT · PRELIMS Medium ☆
Progressive Wave Equation
A transverse wave is represented by
y = Asin(ω \omega ω t − - − kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity?
(a) π A / 2 \pi A/2 π A /2 (b) π A \pi A π A (c) 2π A \pi A π A (d) A A A Show answer and solution
Answer: (c)
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Q92 JEE Main 2010 · AIEEE Medium ☆
Progressive Wave Equation
The equation of a wave on a string of linear mass density 0.04 kg m − 1 0.04\text{ kg m}^{-1} 0.04 kg m − 1 is given by y = 0.02 ( m ) sin [ 2 π ( t 0.04 ( s ) − x 0.50 ( m ) ) ] . y = 0.02\,(\text{m})\sin\left[2\pi\left(\frac{t}{0.04\,(\text{s})} - \frac{x}{0.50\,(\text{m})}\right)\right]. y = 0.02 ( m ) sin [ 2 π ( 0.04 ( s ) t − 0.50 ( m ) x ) ] .
The tension in the string is
(a) 4.0 N 4.0\text{ N} 4.0 N (b) 12.5 N 12.5\text{ N} 12.5 N (c) 0.5 N 0.5\text{ N} 0.5 N (d) 6.25 N 6.25\text{ N} 6.25 N Show answer and solution
Answer: (d)
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Q93 NEET 2009 · AIPMT Medium ☆
Progressive Wave Equation
A wave in a string has an amplitude of 2 cm. The wave travels in the +ve direction of x axis with a speed of 128 m/s. and it is noted that 5 complete waves fit in 4m length of the string. The equation describing the wave is
(a) y = (0.02) m sin (15.7 x − - − 2010t) (b) y = (0.02) m sin (15.7 x + 2010t) (c) y = (0.02) m sin (7.85 x − - − 1005t) (d) y = (0.02) m sin (7.85 x + 1005t) Show answer and solution
Answer: (c)
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Q94 JEE Main 2008 · AIEEE Easy ☆
Progressive Wave Equation
A wave travelling along the x x x -axis is described by the equation y ( x , t ) = 0.005 cos ( α x − β t ) . y(x, t) = 0.005\cos(\alpha x - \beta t). y ( x , t ) = 0.005 cos ( αx − βt ) . If the wavelength and the time period of the wave are 0.08 m 0.08\text{ m} 0.08 m and 2.0 s 2.0\text{ s} 2.0 s , respectively, then α \alpha α and β \beta β in appropriate units are
(a) α = 25.00 π , β = π \alpha = 25.00\pi,\ \beta = \pi α = 25.00 π , β = π (b) α = 0.08 π , β = 2.0 π \alpha = \frac{0.08}{\pi},\ \beta = \frac{2.0}{\pi} α = π 0.08 , β = π 2.0 (c) α = 0.04 π , β = 1.0 π \alpha = \frac{0.04}{\pi},\ \beta = \frac{1.0}{\pi} α = π 0.04 , β = π 1.0 (d) α = 12.50 π , β = π 2.0 \alpha = 12.50\pi,\ \beta = \frac{\pi}{2.0} α = 12.50 π , β = 2.0 π Show answer and solution
Answer: (a)
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Q95 NEET 2008 · AIPMT Easy ☆
Progressive Wave Equation
The wave described by y = 0.25 sin(10π \pi π x − - − 2π \pi π t), where x and y are in metres and t in seconds, is a wave travelling along the
(a) +ve x direction with frequency 1 Hz and wavelength λ \lambda λ = 0.2 m. (b) − - − ve x direction with amplitude 0.25 m and wavelength λ \lambda λ = 0.2 m.(c) − - − ve x direction with frequency 1 Hz.(d) +ve x direction with frequency π \pi π Hz and wavelength λ \lambda λ = 0.2 m. Show answer and solution
Answer: (a)
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Q96 NEET 2008 · AIPMT Easy ☆
Progressive Wave Equation
Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/s. What is the phase difference between the oscillations of two points?
(a) π \pi π (b) π / 6 \pi/6 π /6 (c) π / 3 \pi/3 π /3 (d) 2 π / 3 2\pi/3 2 π /3 Show answer and solution
Answer: (d)
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Q97 NEET 2006 · AIPMT Easy ☆
Progressive Wave Equation
A transverse wave propagating along x-axis is represented by y(x, t) = 8.0 sin (0.5 π \pi π x − - − 4π \pi π t − π -\pi − π /4) where x is in metres and t is in seconds. The speed of the wave is
(a) 8 m/s (b) 4π \pi π m/s (c) 0.5π \pi π m/s (d) π \pi π /4 m/s.Show answer and solution
Answer: (a)
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Q98 JEE Main 2004 · AIEEE Easy ☆
Progressive Wave Equation
The displacement y y y of a particle in a medium can be expressed as, y = 1 0 − 6 sin ( 100 t + 20 x + π 4 ) m y = 10^{-6}\sin\left(100t + 20x + \frac{\pi}{4}\right)\text{ m} y = 1 0 − 6 sin ( 100 t + 20 x + 4 π ) m where t t t is in second and x x x in meter. The speed of the wave is
(a) 20 m/s 20\text{ m/s} 20 m/s (b) 5 m/s 5\text{ m/s} 5 m/s (c) 2000 m/s 2000\text{ m/s} 2000 m/s (d) 5 π m/s 5\pi\text{ m/s} 5 π m/s Show answer and solution
Answer: (b)
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Q99 NEET 2004 · AIPMT Easy ☆
Progressive Wave Equation
The phase difference between two waves. represented by
y1 = 10− - − 6 sin[100t + (x/50) + 0.5] m
y2 = 10− - − 6 cos[100t + (x/50)] m,
where x is expressed in metres and t is exressed in secondss, is approximately.
(a) 1.07 radians (b) 2.07 radians (c) 0.5 radians (d) 1.5 radians Show answer and solution
Answer: (a)
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Q100 JEE Main 2003 · AIEEE Easy ☆
Progressive Wave Equation
The displacement y y y of a wave travelling in the x x x -direction is given by
y = 1 0 − 4 sin ( 600 t − 2 x + π 3 ) metres y = 10^{-4}\sin\left(600t - 2x + \frac{\pi}{3}\right)\text{ metres} y = 1 0 − 4 sin ( 600 t − 2 x + 3 π ) metres
where x x x is expressed in metres and t t t in seconds. The speed of the wave - motion, in ms − 1 \text{ms}^{-1} ms − 1 , is
(a) 300 300 300 (b) 600 600 600 (c) 1200 1200 1200 (d) 200 200 200 Show answer and solution
Answer: (a)
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Q101 NEET 2002 · AIPMT Easy ☆
Progressive Wave Equation
A wave travelling in positive X-direction with a = = = 0.2 m, velocity = 360 ms− 1 {}^{-1} − 1 and λ = \lambda = λ = 60 m, then correct expression for the wave is
(a) y = 0.2 sin [ 2 π ( 6 t + x 60 ) ] y = 0.2\sin\left[2\pi\left(6t + \frac{x}{60}\right)\right] y = 0.2 sin [ 2 π ( 6 t + 60 x ) ] (b) y = 0.2 sin [ π ( 6 t + x 60 ) ] y = 0.2\sin\left[\pi\left(6t + \frac{x}{60}\right)\right] y = 0.2 sin [ π ( 6 t + 60 x ) ] (c) y = 0.2 sin [ 2 π ( 6 t − x 60 ) ] y = 0.2\sin\left[2\pi\left(6t - \frac{x}{60}\right)\right] y = 0.2 sin [ 2 π ( 6 t − 60 x ) ] (d) y = 0.2 sin [ π ( 6 t − x 60 ) ] y = 0.2\sin\left[\pi\left(6t - \frac{x}{60}\right)\right] y = 0.2 sin [ π ( 6 t − 60 x ) ] Show answer and solution
Answer: (c)
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Q102 NEET 2001 · AIPMT Easy ☆
Progressive Wave Equation
The equation of a wave is represented by
y = = = 10− - − 4 sin(100t − x 10 -\frac{x}{10} − 10 x ) m. then the velocity of wave will be
(a) 100 m/s (b) 4 m/s (c) 1000 m/s (d) 10 m/s Show answer and solution
Answer: (c)
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Q103 NEET 1998 · AIPMT Medium ☆
Progressive Wave Equation
A transverse wave is represented by the equation
y = y 0 sin 2 π λ ( v t − x ) y = y_0\sin\frac{2\pi}{\lambda}(vt - x) y = y 0 sin λ 2 π ( v t − x )
For what value of λ \lambda λ is the maximum particle velocity equal to two times the wave velocity?
(a) λ = 2 π y 0 \lambda = 2\pi y_0 λ = 2 π y 0 (b) λ = π y 0 3 \lambda = \frac{\pi y_0}{3} λ = 3 π y 0 (c) λ = π y 0 2 \lambda = \frac{\pi y_0}{2} λ = 2 π y 0 (d) λ = π y 0 \lambda = \pi y_0 λ = π y 0 Show answer and solution
Answer: (d)
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Q104 NEET 1996 · AIPMT Easy ☆
Progressive Wave Equation
The equation of a sound wave is y = 0.0015 sin ( 62.4 x + 316 t ) y = 0.0015\sin(62.4x + 316t) y = 0.0015 sin ( 62.4 x + 316 t ) . The wavelength of this wave is
(a) 0.3 0.3 0.3 unit(b) 0.2 0.2 0.2 unit(c) 0.1 0.1 0.1 unit(d) cannot be calculated Show answer and solution
Answer: (c)
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Q105 NEET 1996 · AIPMT Easy ☆
Progressive Wave Equation
Two sound waves having a phase difference of 6 0 ∘ 60^\circ 6 0 ∘ have path difference of
(a) λ 6 \frac{\lambda}{6} 6 λ (b) λ 3 \frac{\lambda}{3} 3 λ (c) 2 λ 2\lambda 2 λ (d) λ 2 \frac{\lambda}{2} 2 λ Show answer and solution
Answer: (a)
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Q106 NEET 1994 · AIPMT Easy ☆
Progressive Wave Equation
Which one of the following represents a wave?
(a) y = A sin ( ω t − k x ) y = A\sin(\omega t - kx) y = A sin ( ω t − k x ) (b) y = A cos ( a t − b x + c ) y = A\cos(at - bx + c) y = A cos ( a t − b x + c ) (c) y = A sin k x y = A\sin kx y = A sin k x (d) y = A sin ω t y = A\sin\omega t y = A sin ω t Show answer and solution
Answer: (a)
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Q107 NEET 1992 · AIPMT Easy ☆
Progressive Wave Equation
The frequency of sinusodial wave y = 0.40 cos [ 2000 t + 0.80 ] y = 0.40\cos[2000t + 0.80] y = 0.40 cos [ 2000 t + 0.80 ] would be
(a) 1000 π Hz 1000\pi\text{ Hz} 1000 π Hz (b) 2000 Hz 2000\text{ Hz} 2000 Hz (c) 20 Hz 20\text{ Hz} 20 Hz (d) 1000 π Hz \frac{1000}{\pi}\text{ Hz} π 1000 Hz Show answer and solution
Answer: (d)
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Q108 NEET 1990 · AIPMT Easy ☆
Progressive Wave Equation
Velocity of sound waves in air is 330 m/s 330\text{ m/s} 330 m/s . For a particular sound wave in air, a path difference of 40 cm 40\text{ cm} 40 cm is equivalent to phase difference of 1.6 π 1.6\pi 1.6 π . The frequency of this wave is
(a) 165 Hz 165\text{ Hz} 165 Hz (b) 150 Hz 150\text{ Hz} 150 Hz (c) 660 Hz 660\text{ Hz} 660 Hz (d) 330 Hz 330\text{ Hz} 330 Hz Show answer and solution
Answer: (c)
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Q109 NEET 1988 · AIPMT Easy ☆
Progressive Wave Equation
Equation of progressive wave is given by y = 4 sin [ π ( t 5 − x 9 ) + π 6 ] y = 4\sin\left[\pi\left(\frac{t}{5} - \frac{x}{9}\right) + \frac{\pi}{6}\right] y = 4 sin [ π ( 5 t − 9 x ) + 6 π ] where y , x y, x y , x are in cm and t t t is in seconds. Then which of the following is correct?
(a) v = 5 cm v = 5\text{ cm} v = 5 cm (b) λ = 18 cm \lambda = 18\text{ cm} λ = 18 cm (c) a = 0.04 cm a = 0.04\text{ cm} a = 0.04 cm (d) f = 50 Hz f = 50\text{ Hz} f = 50 Hz Show answer and solution
Answer: (b)
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