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MHT CET 2026 (13 Apr, Shift 2) · Impulse & Momentum Conservation

Impulse & Momentum Conservation question from MHT CET 2026 (13 Apr, Shift 2)

Q2MHT CET 2026 · 13 APR · SHIFT 2Easy

Impulse & Momentum Conservation

100100 balls each of mass mm moving with speed vv simultaneously strike a wall normally and reflected back with same speed, in time tt s. The total magnitude of force exerted by the balls on the wall is

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Answer: (b)

  1. Momentum change per ball =mv−(−mv)=2mv= mv - (-mv) = 2mv.
  2. Total change for 100 balls =200mv= 200mv in time tt.
  3. F=Δpt=200mvtF = \frac{\Delta p}{t} = \frac{200mv}{t}
  4. So the answer is (b) 200mv/t200mv/t.
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