Physics Circle home Student Login

Home›Chapters›Thermometry, Thermal Expansion and Calorimetry PYQs›Calorimetry, Latent Heat & Mechanical Equivalent of Heat›Question 51

JEE Main 2011 (AIEEE) · Calorimetry, Latent Heat & Mechanical Equivalent of Heat

Calorimetry, Latent Heat & Mechanical Equivalent of Heat question from JEE Main 2011 (AIEEE)

Q51JEE Main 2011 · AIEEEEasy

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

100 g100\text{ g} of water is heated from 30∘C30^{\circ}\text{C} to 50∘C50^{\circ}\text{C}. Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is 4184 J/kg/K4184\text{ J/kg/K}):

Show answer and solution

Answer: (a)

  1. No work done, so ΔU=Q=mcΔT\Delta U = Q = mc\Delta T.
  2. ΔU=0.1×4184×20=8368\Delta U = 0.1 \times 4184 \times 20 = 8368 J
  3. So the answer is (a) 8.4 kJ.
Report a mistake

More questions on Calorimetry, Latent Heat & Mechanical Equivalent of Heat