125 small water drops of same size fall through air with constant velocity 4 cm/s. They coalesce to form a big drop. The terminal velocity of the big drop is (a) 0.5 m/s (b) 1 m/s (c) 1.5 m/s (d) 2.5 m/s

Answer: (b). v ∝ r² and R = n1/3r, so v' = n2/3v. n = 125 ⇒ n2/3 = 25 v' = 25 × 4 = 100 cm/s = 1 m/s So the answer is (b) 1 m/s.

125 small water drops of same size fall through air with constant… | MHT CET 2025 (26 Apr, Shift 1)

Q16MHT CET 2025 · 26 APR · SHIFT 1Easy

Terminal Velocity

125 small water drops of same size fall through air with constant velocity $4\text{ cm/s}$ . They coalesce to form a big drop. The terminal velocity of the big drop is

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Answer: (b)

$v \propto r^2$ and $R = n^{1/3}r$ , so $v' = n^{2/3}v$ .
$n = 125 \Rightarrow n^{2/3} = 25$
$v' = 25 \times 4 = 100$ cm/s $= 1$ m/s
So the answer is (b) $1$ m/s.

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