300 cal. of heat is given to a heat engine and it rejects 225 cal. If source temperature is 227 ° C, then the temperature of sink will be ______________ ° C. Numerical answer type. Work it out, then open the answer.

Answer: 102. Treating it as a Carnot engine: (T₂)/(T₁) = (Q₂)/(Q₁) = (225)/(300) = 0.75. T₁ = 227 + 273 = 500 K ⇒ T₂ = 375 K T₂ = 375 - 273 = 102

300 cal. of heat is given to a heat engine and it rejects 225 cal. If… | JEE Main 2022 (29 Jun, Shift 1)

Q37JEE Main 2022 · 29 JUN · SHIFT 1Medium

Heat Engines, Refrigerators & Second Law

300 cal. of heat is given to a heat engine and it rejects 225 cal. If source temperature is 227 $^\circ$ C, then the temperature of sink will be ______________ $^\circ$ C.

Numerical answer type. Work it out, then open the answer.

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Answer: 102

Treating it as a Carnot engine: $\frac{T_2}{T_1} = \frac{Q_2}{Q_1} = \frac{225}{300} = 0.75$ .
$T_1 = 227 + 273 = 500\text{ K} \Rightarrow T_2 = 375\text{ K}$
$T_2 = 375 - 273 = 102^\circ\text{C}$

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