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JEE Main 2018 (15 Apr, Shift 2) · Beats

Beats question from JEE Main 2018 (15 Apr, Shift 2)

Q59JEE Main 2018 · 15 APR · SHIFT 2Medium

Beats

5 beats / second are heard when a tuning fork is sounded with a sonometer wire under tension, when the length of the sonometer wire is either 0.95 m or 1 m. The frequency of the fork will be:

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Answer: (a)

  1. f∝1Lf \propto \dfrac{1}{L}: 0.95 m wire gives n+5n + 5, 1 m wire gives n−5n - 5.
  2. (n+5)×0.95=(n−5)×1(n + 5) \times 0.95 = (n - 5) \times 1
  3. 0.05n=9.75⇒n=195 Hz0.05n = 9.75 \Rightarrow n = 195\text{ Hz}
  4. So the answer is (a) 195 Hz.
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