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JEE Main 2023 (13 Apr, Shift 2) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from JEE Main 2023 (13 Apr, Shift 2)

Q39JEE Main 2023 · 13 APR · SHIFT 2Easy

Electric Charge & Coulomb's Law

A 10 μC10\ \mu\text{C} charge is divided into two parts and placed at 1 cm1\text{ cm} distance so that the repulsive force between them is maximum. The charges of the two parts are:

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Answer: (b)

  1. F∝q(Q−q)F \propto q(Q-q); dFdq=Q−2q=0⇒q=Q2\dfrac{dF}{dq} = Q - 2q = 0 \Rightarrow q = \dfrac{Q}{2}.
  2. q=102=5 μCq = \dfrac{10}{2} = 5\ \mu\text{C} each.
  3. So the answer is (b) 5 μC,5 μC5\ \mu\text{C}, 5\ \mu\text{C}.
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