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MHT CET 2026 (14 May, Shift 2) · LC Oscillations

LC Oscillations question from MHT CET 2026 (14 May, Shift 2)

Q3MHT CET 2026 · 14 MAY · SHIFT 2Easy

LC Oscillations

A $10\ \mu$ F capacitor is charged to $25$ V of potential. The battery is then disconnected and a pure $100$ mH coil is connected across the capacitor so that L-C oscillations are set up. The maximum current in the coil is

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Answer: (a)

$\frac{1}{2}CV^2 = \frac{1}{2}LI_{max}^2 \Rightarrow I_{max} = V\sqrt{C/L}$
$I_{max} = 25\sqrt{\frac{10\times10^{-6}}{0.1}} = 25\times 0.01$
$I_{max} = 0.25$ A, so the answer is (a).

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