A 10 m long wire of resistance 20 Ω is connected in series with a battery of emf 3 V (negligible internal resistance) and a resistance of 10 Ω. The potential gradient along the wire is (a) 3 V/m (b) 0.1 V/m (c) 0.2 V/m (d) 0.3 V/m

Answer: (c). I = (3)/(20+10) = 0.1 A Vwire = 0.1× 20 = 2 V k = 2/10 = 0.2 V/m So the answer is (c) 0.2 V/m.

A 10 m long wire of resistance 20 Ω is connected in series with a… | MHT CET 2023 (13 May, Shift 2)

Q42MHT CET 2023 · 13 MAY · SHIFT 2Medium

Potentiometer

A $10\text{ m}$ long wire of resistance $20\ \Omega$ is connected in series with a battery of emf $3\text{ V}$ (negligible internal resistance) and a resistance of $10\ \Omega$ . The potential gradient along the wire is

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Answer: (c)

$I = \dfrac{3}{20+10} = 0.1$ A
$V_{wire} = 0.1\times 20 = 2$ V
$k = \dfrac{2}{10} = 0.2$ V/m
So the answer is (c) 0.2 V/m.

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Potentiometer question from MHT CET 2023 (13 May, Shift 2)

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