Physics Circle home Student Login

Home›Chapters›Thermometry, Thermal Expansion and Calorimetry PYQs›Calorimetry, Latent Heat & Mechanical Equivalent of Heat›Question 22

JEE Main 2022 (24 Jun, Shift 2) · Calorimetry, Latent Heat & Mechanical Equivalent of Heat

Calorimetry, Latent Heat & Mechanical Equivalent of Heat question from JEE Main 2022 (24 Jun, Shift 2)

Q22JEE Main 2022 · 24 JUN · SHIFT 2Medium

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

A 100 g of iron nail is hit by a 1.5 kg hammer striking at a velocity of 60 ms−^{-}1. What will be the rise in the temperature of the nail if one fourth of energy of the hammer goes into heating the nail? [Specific heat capacity of iron = 0.42 Jg−^{-}1 ∘C−^{\circ}\text{C}^{-}1]

Show answer and solution

Answer: (c)

  1. KE of hammer =12(1.5)(60)2=2700 J= \tfrac{1}{2}(1.5)(60)^2 = 2700\text{ J}; heat to nail =14×2700=675 J= \tfrac{1}{4} \times 2700 = 675\text{ J}.
  2. ΔT=Qmc=675100×0.42=16.07∘C\Delta T = \dfrac{Q}{mc} = \dfrac{675}{100 \times 0.42} = 16.07^{\circ}\text{C}
  3. So the answer is (c) 16.07∘C16.07^{\circ}\text{C}.
Report a mistake

More questions on Calorimetry, Latent Heat & Mechanical Equivalent of Heat