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NEET 1991 (AIPMT) · Self-Inductance & Energy

Self-Inductance & Energy question from NEET 1991 (AIPMT)

Q88NEET 1991 · AIPMTEasy

Self-Inductance & Energy

A 100 millihenry coil carries a current of 1 A. Energy stored in its magnetic field is

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Answer: (c)

$U = \tfrac12 L I^2 = \tfrac12\times0.1\times1^2$
$U = 0.05\text{ J}$
So the answer is (c) $0.05\text{ J}$ .

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