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NEET 2016 (Phase 2) · Pure R, L and C Circuits

Pure R, L and C Circuits question from NEET 2016 (Phase 2)

Q62NEET 2016 · PHASE 2Difficult

Pure R, L and C Circuits

A 100 Ω\Omega resistance and a capacitor of 100 Ω\Omega reactance are connected in series across a 220 V source. When the capacitor is 50% charged, the peak value of the displacement current is

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Answer: (a)

  1. Displacement current in the capacitor equals the conduction current in the circuit at every instant, so the charge state does not matter.
  2. Z=R2+XC2=1002+1002=1002 ΩZ = \sqrt{R^2 + X_C^2} = \sqrt{100^2 + 100^2} = 100\sqrt{2}\ \Omega
  3. Taking 220 V as rms: V0=2202V_0 = 220\sqrt{2} V, so I0=22021002=2.2I_0 = \frac{220\sqrt{2}}{100\sqrt{2}} = 2.2 A.
  4. So the answer is (a) 2.2 A.
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