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MHT CET 2025 (5 May, Shift 2) · Potentiometer

Potentiometer question from MHT CET 2025 (5 May, Shift 2)

Q22MHT CET 2025 · 5 MAY · SHIFT 2Easy

Potentiometer

A 2.5 V battery is connected to a potentiometer wire. A cell of e.m.f. 1.08 V is balanced by the voltage drop across 2.16 m of wire. The length of the potentiometer wire is

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Answer: (c)

  1. Potential gradient k=El=1.082.16=0.5 V/mk = \frac{E}{l} = \frac{1.08}{2.16} = 0.5\ \text{V/m}.
  2. The whole wire carries the battery p.d.: L=Vk=2.50.5=5 mL = \frac{V}{k} = \frac{2.5}{0.5} = 5\ \text{m}.
  3. So the answer is (c) 5 m.
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