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JEE Main 2023 (15 Apr, Shift 1) · Rotating Conductors & AC Generator

Rotating Conductors & AC Generator question from JEE Main 2023 (15 Apr, Shift 1)

Q20JEE Main 2023 · 15 APR · SHIFT 1Easy

Rotating Conductors & AC Generator

A 20 cm20\text{ cm} long metallic rod is rotated with 210 rpm210\text{ rpm} about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field 0.2 T0.2\text{ T} parallel to the axis exists everywhere. The emf developed between the centre and the ring is ____________ mV\text{mV}.

Take π=227\pi = \frac{22}{7}

Numerical answer type. Work it out, then open the answer.

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Answer: 88

  1. ω=2π×21060=7π=7×227=22 rad/s\omega = \dfrac{2\pi \times 210}{60} = 7\pi = 7 \times \dfrac{22}{7} = 22\text{ rad/s}
  2. e=12Bωl2=12×0.2×22×(0.2)2e = \tfrac{1}{2}B\omega l^2 = \tfrac{1}{2} \times 0.2 \times 22 \times (0.2)^2
  3. e=0.088 V=88 mVe = 0.088\text{ V} = 88\text{ mV}
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