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NEET 2010 (AIPMT, Prelims) · AC Generator & Transformer

AC Generator & Transformer question from NEET 2010 (AIPMT, Prelims)

Q52NEET 2010 · AIPMT · PRELIMSEasy

AC Generator & Transformer

A 220 volt input is supplied to a transformer. The output circuit draws a current of 2.0 ampere at 440 volts. If the efficiency of the transformer is 80%, the current drwn by the primary windings of the transformer is

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Answer: (d)

  1. Pout=440×2=880 WP_{out} = 440 \times 2 = 880\text{ W}
  2. Pin=8800.8=1100 WP_{in} = \dfrac{880}{0.8} = 1100\text{ W}
  3. Ip=1100220=5.0 AI_p = \dfrac{1100}{220} = 5.0\text{ A}
  4. So the answer is (d) 5.0 ampere.
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