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JEE Main 2015 (10 Apr, Shift 1) · Ampere's Law, Cylinders, Solenoid & Toroid

Ampere's Law, Cylinders, Solenoid & Toroid question from JEE Main 2015 (10 Apr, Shift 1)

Q54JEE Main 2015 · 10 APR · SHIFT 1Medium

Ampere's Law, Cylinders, Solenoid & Toroid

A 25 cm long solenoid has radius 2 cm and 500 total number of turns. It carries a current of 15 A. If it is equivalent to a magnet of the same size and magnetization M⃗\vec{M} (magnetic moment/volume), then ∣M∣→\overrightarrow{|M|} is:

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Answer: (b)

  1. Magnetic moment m=NIAm = N I A and volume V=ALV = A L, so M=mV=NILM = \frac{m}{V} = \frac{N I}{L}.
  2. M=500×150.25=30000M = \frac{500 \times 15}{0.25} = 30000 A/m
  3. So the answer is (b) 30000 A m−1^{-1}.
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