A 4 capacitor is charged to 400 V. If its plates are joined through a resistance of 2 kΩ, then heat produced in the resistance is (a) 0.64 J (b) 1.28 J (c) 0.16 J (d) 0.32 J

Answer: (d). All stored energy becomes heat in the resistor (the value of R does not matter). H = 1/2CV² = 1/2 × 4 × 10⁻⁶ × (400)² H = 2 × 10⁻⁶ × 1.6 × 10⁵ = 0.32 J So the answer is (d) 0.32 J.

A 4 capacitor is charged to 400 V. If its plates are joined through a… | NEET 1995 (AIPMT)

Q41NEET 1995 · AIPMTEasy

Energy Stored & Force between Plates

A $4\ \mu\text{F}$ capacitor is charged to $400\text{ V}$ . If its plates are joined through a resistance of $2\text{ k}\Omega$ , then heat produced in the resistance is

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Answer: (d)

All stored energy becomes heat in the resistor (the value of $R$ does not matter).
$H = \frac{1}{2}CV^2 = \frac{1}{2} \times 4 \times 10^{-6} \times (400)^2$
$H = 2 \times 10^{-6} \times 1.6 \times 10^{5} = 0.32\text{ J}$
So the answer is (d) $0.32\text{ J}$ .

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