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JEE Main 2026 (21 Jan, Shift 1) · Inertia, First & Second Laws

Inertia, First & Second Laws question from JEE Main 2026 (21 Jan, Shift 1)

Q3JEE Main 2026 · 21 JAN · SHIFT 1Medium

Inertia, First & Second Laws

A 4 kg mass moves under the influence of a force F⃗=(4t3i^−3tj^) N\vec{F} = \left(4t^3\hat{i} - 3t\hat{j}\right)\text{ N} where tt is the time in second. If mass starts from origin at t=0t = 0, the velocity and position after t=2 st = 2\text{ s} will be:

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Answer: (c)

  1. a⃗=F⃗4=t3i^−34tj^\vec{a} = \frac{\vec{F}}{4} = t^3\hat{i} - \frac{3}{4}t\hat{j}
  2. v⃗=t44i^−3t28j^\vec{v} = \frac{t^4}{4}\hat{i} - \frac{3t^2}{8}\hat{j}; at t=2t = 2: v⃗=4i^−32j^\vec{v} = 4\hat{i} - \frac{3}{2}\hat{j}
  3. r⃗=t520i^−t38j^\vec{r} = \frac{t^5}{20}\hat{i} - \frac{t^3}{8}\hat{j}; at t=2t = 2: r⃗=85i^−j^\vec{r} = \frac{8}{5}\hat{i} - \hat{j}
  4. So the answer is (c).
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