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MHT CET 2026 (19 May, Shift 2) · LC Oscillations

LC Oscillations question from MHT CET 2026 (19 May, Shift 2)

Q2MHT CET 2026 · 19 MAY · SHIFT 2Easy

LC Oscillations

A $40\ \mu$ F capacitor is charged to $10$ volts of potential. The battery is disconnected, and a pure $100$ mH coil is connected across the capacitor so that LC oscillations are set up. Then, the maximum current in the coil is:

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Answer: (d)

Energy conservation: $\frac{1}{2}CV^2 = \frac{1}{2}LI_{max}^2$
$I_{max} = V\sqrt{\frac{C}{L}} = 10\sqrt{\frac{40\times10^{-6}}{0.1}} = 10\times 0.02$
$I_{max} = 0.20$ A, so the answer is (d).

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