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JEE Main 2025 (28 Jan, Shift 2) · Archimedes' Principle & Floatation

Archimedes' Principle & Floatation question from JEE Main 2025 (28 Jan, Shift 2)

Q5JEE Main 2025 · 28 JAN · SHIFT 2Easy

Archimedes' Principle & Floatation

A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water?

(Given: density of water = 1000 kg m-3)

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Answer: (b)

Floating: displaced water mass = cube mass = 400 g, so submerged volume $= 400$ cm $^{3}$ (water is 1 g/cm $^{3}$ ).
Total volume $= 10^{3} = 1000$ cm $^{3}$ .
Volume outside $= 1000 - 400 = 600$ cm $^{3}$
So the answer is (b) 600 cm $^{3}$ .

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