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MHT CET 2024 (3 May, Shift 2) · Pure R, L and C Circuits

Pure R, L and C Circuits question from MHT CET 2024 (3 May, Shift 2)

Q26MHT CET 2024 · 3 MAY · SHIFT 2Easy

Pure R, L and C Circuits

A 42 mH inductor is connected to 200 V,50 Hz200\text{ V}, 50\text{ Hz} a.c. supply. The r.m.s. value of current in the circuit will be nearly [ Take π=227\pi = \frac{22}{7} ]

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Answer: (a)

  1. XL=2πfL=2×227×50×0.042=13.2 ΩX_L = 2\pi fL = 2 \times \frac{22}{7} \times 50 \times 0.042 = 13.2\ \Omega
  2. Irms=VrmsXL=20013.2=15.15I_{rms} = \frac{V_{rms}}{X_L} = \frac{200}{13.2} = 15.15 A
  3. So the answer is (a) 15.1515.15 A.
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