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JEE Main 2020 (7 Jan, Shift 2) · Charge Sharing & Loss of Energy

Charge Sharing & Loss of Energy question from JEE Main 2020 (7 Jan, Shift 2)

Q27JEE Main 2020 · 7 JAN · SHIFT 2Easy

Charge Sharing & Loss of Energy

A 60 pF capacitor is fully charged by a 20 V supply. It is then disconnected from the supply and is conneced to another uncharged 60 pF capacitor in parallel. The electrostatic energy that is lost in this process by the time the charge is redistributed between them is (in nJ) _____

Numerical answer type. Work it out, then open the answer.

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Answer: 6

  1. For two identical capacitors, loss =14CV2= \frac{1}{4}CV^2.
  2. ΔU=14×60×10−12×202=6×10−9\Delta U = \frac{1}{4} \times 60 \times 10^{-12} \times 20^2 = 6 \times 10^{-9} J
  3. Energy lost =6= 6 nJ
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