A 600 pF capacitor is charged by 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. Electrostatic energy lost in the process is ____________ Numerical answer type. Work it out, then open the answer.

Answer: 6. For two equal capacitors, loss = 1/4CV². Δ U = 1/4 × 600 × 10⁻¹² × 200² = 6 × 10⁻⁶ J Energy lost = 6 μ J

A 600 pF capacitor is charged by 200 V supply. It is then… | JEE Main 2023 (8 Apr, Shift 2)

Q15JEE Main 2023 · 8 APR · SHIFT 2Easy

Charge Sharing & Loss of Energy

A $600\text{ pF}$ capacitor is charged by $200\text{ V}$ supply. It is then disconnected from the supply and is connected to another uncharged $600\text{ pF}$ capacitor. Electrostatic energy lost in the process is ____________ $\mu\text{J}$

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 6

For two equal capacitors, loss $= \frac{1}{4}CV^2$ .
$\Delta U = \frac{1}{4} \times 600 \times 10^{-12} \times 200^2 = 6 \times 10^{-6}$ J
Energy lost $= 6\ \mu$ J

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