A 72 Ω galvanometer is shunted by a resistance of 8 Ω. The percentage of the total current which passes through the galvanometer is: (a) 0.1% (b) 10% (c) 25% (d) 0.25%

Answer: (b). Fraction through galvanometer Ig/I = (S)/(S + G). Ig/I = (8)/(8 + 72) = 1/10 = 10% So the answer is (b) 10%.

A 72 Ω galvanometer is shunted by a resistance of 8 Ω. The percentage… | JEE Main 2022 (27 Jun, Shift 1)

Q102JEE Main 2022 · 27 JUN · SHIFT 1Easy

Kirchhoff's Laws & Measuring Instruments

A 72 $\Omega$ galvanometer is shunted by a resistance of 8 $\Omega$ . The percentage of the total current which passes through the galvanometer is:

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Answer: (b)

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