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JEE Main 2020 (3 Sep, Shift 1) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from JEE Main 2020 (3 Sep, Shift 1)

Q61JEE Main 2020 · 3 SEP · SHIFT 1Difficult

Power, Power Factor & Wattless Current

A 750 Hz, 20 V (rms) source is connected to a resistance of 100 Ω\Omega, an inductance of 0.1803 H and a capacitance of 10 μ\muF all in series. The time in which the resistance (heat capacity 2 J/oC) will get heated by 10oC. (assume no loss of heat to the surroudnings) is close to:

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Answer: (a)

  1. ω=2π×750≈4712\omega = 2\pi\times 750 \approx 4712 rad/s
  2. XL=4712×0.1803≈849.6 ΩX_L = 4712\times 0.1803 \approx 849.6\ \Omega, XC=14712×10−5≈21.2 ΩX_C = \frac{1}{4712\times 10^{-5}} \approx 21.2\ \Omega
  3. Z=1002+828.42≈834.4 ΩZ = \sqrt{100^2 + 828.4^2} \approx 834.4\ \Omega, I=20/834.4≈0.024I = 20/834.4 \approx 0.024 A
  4. P=I2R≈0.0574P = I^2 R \approx 0.0574 W; heat needed =2×10=20= 2\times 10 = 20 J
  5. t=20/0.0574≈348t = 20/0.0574 \approx 348 s, so the answer is (a).
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