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JEE Main 2013 (22 Apr, Shift 1) · Doppler Effect

Doppler Effect question from JEE Main 2013 (22 Apr, Shift 1)

Q72JEE Main 2013 · 22 APR · SHIFT 1Medium

Doppler Effect

A and B are two sources generating sound waves. A listener is situated at C. The frequency of the source at A is 500 Hz. A, now, moves towards C with a speed 4 m/s. The number of beats heard at C is 6. When A moves away from C with speed 4 m/s, the number of beats heard at C is 18. The speed of sound is 340 m/s. The frequency of the source at B is:

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Answer: (c)

  1. A approaching C: fA=500×340340−4=500×340336≈506f_A = 500 \times \frac{340}{340-4} = 500 \times \frac{340}{336} \approx 506 Hz
  2. A receding from C: fA′=500×340344≈494f_A' = 500 \times \frac{340}{344} \approx 494 Hz
  3. Beats: ∣506−fB∣=6|506 - f_B| = 6 and ∣494−fB∣=18|494 - f_B| = 18
  4. Both hold only for fB=512f_B = 512 Hz.
  5. So the answer is (c) 512 Hz.
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