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MHT CET 2023 (12 May, Shift 1) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from MHT CET 2023 (12 May, Shift 1)

Q33MHT CET 2023 · 12 MAY · SHIFT 1Medium

Force on Current-Carrying Conductors

A,BA, B and CC are three parallel conductors of equal lengths and carry currents I, I and 2I respectively as shown in figure. Distance ABAB and BCBC is same as 'dd'. If 'F1F_1' is the force exerted by BB on AA and F2F_2 is the force exerted by CC on AA, then

Figure

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Answer: (b)

  1. F1F_1 (B on A): same direction currents, attraction towards B; magnitude μ0I⋅I2πd\frac{\mu_0 I\cdot I}{2\pi d} per unit length.
  2. F2F_2 (C on A): opposite currents, repulsion away from C; magnitude μ0I⋅2I2π(2d)=μ0I22πd\frac{\mu_0 I\cdot2I}{2\pi(2d)} = \frac{\mu_0 I^2}{2\pi d}.
  3. Equal magnitudes, opposite directions: F1=−F2F_1 = -F_2
  4. So the answer is (b).
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