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JEE Main 2022 (27 Jul, Shift 1) · Friction Basics

Friction Basics question from JEE Main 2022 (27 Jul, Shift 1)

Q14JEE Main 2022 · 27 JUL · SHIFT 1Medium

Friction Basics

A bag is gently dropped on a conveyor belt moving at a speed of 2 m/s2\text{ m/s}. The coefficient of friction between the conveyor belt and bag is 0.40.4. Initially, the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion, is: [Take g=10 m/s2g = 10\text{ m/s}^{2} ]

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Answer: (b)

  1. Friction accelerates the bag: a=μg=0.4×10=4 m/s2a = \mu g = 0.4 \times 10 = 4\text{ m/s}^2.
  2. Bag slips until it reaches the belt speed 2 m/s2\text{ m/s}: v2=2asv^2 = 2as
  3. s=222×4=0.5 ms = \dfrac{2^2}{2 \times 4} = 0.5\text{ m}
  4. So the answer is (b) 0.5 m.
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