A bakelite beaker has volume capacity of 500 cc at 30oC. When it is partially filled with Vm volume (at 30oC) of mercury, it is found that the unfilled volume of the beaker remains constant as temperature is varied. If γ (beaker) = 6 × 10–6oC–1 and γ (mercury) = 1.5 × 10–4oC–1, where γ is the coefficient of volume expansion, then Vm (in cc) is close to ____. Numerical answer type. Work it out, then open the answer.

Answer: 20. Unfilled volume constant: Vmγm = Vbγb. Vm = 500 × 6×10⁻⁶1.5×10⁻⁴ = 20 cc Answer: 20 cc.

A bakelite beaker has volume capacity of 500 cc at 30oC. When it is… | JEE Main 2020 (3 Sep, Shift 1)

Q57JEE Main 2020 · 3 SEP · SHIFT 1Difficult

Thermometry & Thermal Expansion

A bakelite beaker has volume capacity of 500 cc at 30oC. When it is partially filled with Vm volume (at 30oC) of mercury, it is found that the unfilled volume of the beaker remains constant as temperature is varied. If $\gamma$ (beaker) = 6 × 10–6oC–1 and $\gamma$ (mercury) = 1.5 × 10–4oC–1, where $\gamma$ is the coefficient of volume expansion, then Vm (in cc) is close to ____.

Numerical answer type. Work it out, then open the answer.

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Answer: 20

Unfilled volume constant: $V_m\gamma_m = V_b\gamma_b$ .
$V_m = \dfrac{500 \times 6\times10^{-6}}{1.5\times10^{-4}} = 20$ cc
Answer: 20 cc.

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Thermometry & Thermal Expansion question from JEE Main 2020 (3 Sep, Shift 1)

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