A balanced meter bridge is shown in the circuit diagram. The meter bridge wire has resistance 2 (Ω)/(cm). The current drawn from the battery is (Internal resistance of the battery is negligible) (a) 0.6 A (b) 0.8 A (c) 0.95 A (d) 1.05 A

Answer: (d). Balance: 3/x = 30/70 ⇒ x = 7 Ω Gap branch: 3 + 7 = 10 Ω, current 10/10 = 1 A Wire (100 cm): 100 × 2 = 200 Ω, current 10/200 = 0.05 A Total I = 1 + 0.05 = 1.05 A So the answer is (d) 1.05 A.

A balanced meter bridge is shown in the circuit diagram. The meter… | MHT CET 2026 (20 May, Shift 1)

Q6MHT CET 2026 · 20 MAY · SHIFT 1Medium

Wheatstone Bridge & Metre Bridge

A balanced meter bridge is shown in the circuit diagram. The meter bridge wire has resistance $2\ \frac{\Omega}{cm}$ . The current drawn from the battery is (Internal resistance of the battery is negligible)

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Answer: (d)

Balance: $\dfrac{3}{x} = \dfrac{30}{70} \Rightarrow x = 7\ \Omega$
Gap branch: $3 + 7 = 10\ \Omega$ , current $\dfrac{10}{10} = 1$ A
Wire (100 cm): $100 \times 2 = 200\ \Omega$ , current $\dfrac{10}{200} = 0.05$ A
Total $I = 1 + 0.05 = 1.05$ A
So the answer is (d) $1.05$ A.

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Wheatstone Bridge & Metre Bridge question from MHT CET 2026 (20 May, Shift 1)

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