Motion Under Gravity
A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18 s. What is the value of v?
(Take g = 10 m/s2)
Show answer and solution
Answer: (a)
- First ball at has fallen .
- Second ball moves for :
- They meet:
- So the answer is (a) 75 m/s.