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JEE Main 2022 (25 Jul, Shift 2) · Time of Flight, Maximum Height & Range

Time of Flight, Maximum Height & Range question from JEE Main 2022 (25 Jul, Shift 2)

Q22JEE Main 2022 · 25 JUL · SHIFT 2Easy

Time of Flight, Maximum Height & Range

A ball is projected from the ground with a speed 15 ms ${}^{-1}$ at an angle $\theta$ with horizontal so that its range and maximum height are equal,

then 'tan $\theta$ ' will be equal to:

Show answer and solution

Answer: (d)

$\frac{R}{H} = \frac{4}{\tan\theta}$ (independent of speed)
$R = H \Rightarrow \tan\theta = 4$
So the answer is (d) 4.

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