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JEE Main 2022 (26 Jun, Shift 2) · Motion Under Gravity

Motion Under Gravity question from JEE Main 2022 (26 Jun, Shift 2)

Q28JEE Main 2022 · 26 JUN · SHIFT 2Medium

Motion Under Gravity

A ball is projected vertically upward with an initial velocity of 50 ms ${}^{-1}$ at t = 0s. At t = 2s, another ball is projected vertically upward with same velocity. At t = __________ s, second ball will meet the first ball (g = 10 ms ${}^{-2}$ ).

Numerical answer type. Work it out, then open the answer.

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Answer: 6

$y_1 = 50t - 5t^2$ , $y_2 = 50(t-2) - 5(t-2)^2$
Meet when $y_1 = y_2$ : $0 = -100 + 20t - 20$
$t = 6\text{ s}$

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