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NEET 2022 (Phase 1) · Velocity, Momentum & Energy in Flight

Velocity, Momentum & Energy in Flight question from NEET 2022 (Phase 1)

Q11NEET 2022 · PHASE 1Easy

Velocity, Momentum & Energy in Flight

A ball is projected with a velocity, 10 ms−1{}^{-1}, at an angle of 60∘^\circ with the vertical direction. Its speed at the highest point of its trajectory will be

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Answer: (b)

  1. 60∘60^\circ with the vertical means θ=30∘\theta = 30^\circ with the horizontal.
  2. At the top, speed =ucos⁡θ=10cos⁡30∘=10×32= u\cos\theta = 10\cos 30^\circ = 10 \times \frac{\sqrt{3}}{2}
  3. So the answer is (b) 53 m s−15\sqrt{3}\text{ m s}^{-1}.
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