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JEE Main 2022 (29 Jul, Shift 1) · Conservation of Energy

Conservation of Energy question from JEE Main 2022 (29 Jul, Shift 1)

Q20JEE Main 2022 · 29 JUL · SHIFT 1Easy

Conservation of Energy

A ball is projected with kinetic energy E, at an angle of 60∘60^\circ to the horizontal. The kinetic energy of this ball at the highest point of its flight will become:

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Answer: (c)

  1. At the top only the horizontal velocity ucos⁡θu\cos\theta remains, so Ktop=Ecos⁡2θK_{top} = E\cos^2\theta.
  2. Ktop=Ecos⁡260∘=E×14K_{top} = E\cos^2 60^\circ = E \times \frac{1}{4}
  3. So the answer is (c) E4\frac{E}{4}.
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