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JEE Main 2022 (29 Jul, Shift 2) · Motion Under Gravity

Motion Under Gravity question from JEE Main 2022 (29 Jul, Shift 2)

Q23JEE Main 2022 · 29 JUL · SHIFT 2Medium

Motion Under Gravity

A ball is released from a height h. If $t_1$ and $t_2$ be the time required to complete first half and second half of the distance respectively. Then, choose the correct relation between $t_1$ and $t_2$ .

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Answer: (d)

First half: $\frac{h}{2} = \frac{1}{2}gt_1^2 \Rightarrow t_1 = \sqrt{h/g}$
Whole height: $T = \sqrt{2h/g} = \sqrt{2}\,t_1$
$t_2 = T - t_1 = (\sqrt{2} - 1)t_1$
So the answer is (d) $t_2 = (\sqrt{2} - 1)t_1$ .

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