Motion Under Gravity question from MHT CET 2024 (15 May, Shift 2)

Answer: (b)

1. Free fall from rest: $h = \frac{1}{2}gt^2 \Rightarrow h \propto t^2$, with $H = \frac{1}{2}gT^2$.
2. Fallen in $\frac{T}{4}$: $\frac{H}{16}$
3. Height above ground $= H - \frac{H}{16} = \frac{15H}{16}$
4. So the answer is (b) $\frac{15H}{16}$.