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NEET 2020 (Phase 1) · Motion Under Gravity

Motion Under Gravity question from NEET 2020 (Phase 1)

Q39NEET 2020 · PHASE 1Easy

Motion Under Gravity

A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 m/s. The height of the tower is: (g = 10 m/s2)

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Answer: (c)

$v^2 = u^2 + 2gh$
$h = \frac{80^2 - 20^2}{2 \times 10} = \frac{6400 - 400}{20} = 300$ m
So the answer is (c) 300 m.

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