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NEET 2005 (AIPMT) · Motion Under Gravity

Motion Under Gravity question from NEET 2005 (AIPMT)

Q53NEET 2005 · AIPMTEasy

Motion Under Gravity

A ball is thrown vertically upward. It has a speed of 10 m/sec when it has reached one half of its maximum height. How high does the ball rise?

(Take g = 10 m/s2.)

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Answer: (a)

  1. Maximum height: u2=2gHu^2 = 2gH
  2. At H/2H/2: v2=u2−2gH2=2gH−gH=gHv^2 = u^2 - 2g\frac{H}{2} = 2gH - gH = gH
  3. 102=10×H⇒H=1010^2 = 10 \times H \Rightarrow H = 10 m
  4. So the answer is (a) 10 m.
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