A ball is thrown vertically upward with an initial velocity of 150 m/s. The ratio of velocity after 3 s and 5 s is x+1/x. The value of x is ___________. take, g = 10 m/s² (a) -5 (b) 10 (c) 5 (d) 6

Answer: (c). v = u - gt: v₃ = 150 - 30 = 120 m/s, v₅ = 150 - 50 = 100 m/s (v₃)/(v₅) = (120)/(100) = 6/5 = x+1/x ⇒ x = 5. So the answer is (c) 5.

A ball is thrown vertically upward with an initial velocity of 150… | JEE Main 2023 (12 Apr, Shift 1)

Q15JEE Main 2023 · 12 APR · SHIFT 1Easy

Motion Under Gravity

A ball is thrown vertically upward with an initial velocity of $150\text{ m/s}$ . The ratio of velocity after $3\text{ s}$ and $5\text{ s}$ is $\frac{x+1}{x}$ . The value of $x$ is ___________.

$\{$ take, $g = 10\text{ m/s}^2\}$

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Answer: (c)

$v = u - gt$ : $v_3 = 150 - 30 = 120$ m/s, $v_5 = 150 - 50 = 100$ m/s
$\frac{v_3}{v_5} = \frac{120}{100} = \frac{6}{5} = \frac{x+1}{x}$
$\Rightarrow x = 5$ . So the answer is (c) 5.

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