A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes upto 2 m height further, find the magnitude of the force. (consider g = 10 m/s²). (a) 4 N (b) 16 N (c) 20 N (d) 22 N

Answer: (d). From start (rest) to top (rest): Whand + Wgravity = Δ K = 0. Ball rises 0.2 + 2 = 2.2 m in total: F(0.2) = mg(2.2) F = (0.2 × 10 × 2.2)/(0.2) = 22 N So the answer is (d) 22 N.

A ball of mass 0.2 kg is thrown vertically upwards by applying a… | JEE Main 2006 (AIEEE)

Q27JEE Main 2006 · AIEEEMedium

Work-Energy Theorem

A ball of mass $0.2\text{ kg}$ is thrown vertically upwards by applying a force by hand. If the hand moves $0.2\text{ m}$ while applying the force and the ball goes upto $2\text{ m}$ height further, find the magnitude of the force. (consider $g = 10\text{ m/s}^2$ ).

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Answer: (d)

From start (rest) to top (rest): $W_{hand} + W_{gravity} = \Delta K = 0$ .
Ball rises $0.2 + 2 = 2.2\text{ m}$ in total: $F(0.2) = mg(2.2)$
$F = \frac{0.2 \times 10 \times 2.2}{0.2} = 22\text{ N}$
So the answer is (d) $22\text{ N}$ .

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