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NEET 1998 (AIPMT) · Circular Motion (Related PYQs)

Circular Motion (Related PYQs) question from NEET 1998 (AIPMT)

Q11NEET 1998 · AIPMTEasy

Circular Motion (Related PYQs)

A ball of mass 0.25 kg0.25\text{ kg} attached to the end of a string of length 1.96 m1.96\text{ m} is moving in a horizontal circle. The string will break if the tension is more than 25 N25\text{ N}. What is the maximum speed with which the ball can be moved?

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Answer: (a)

  1. Tension provides the centripetal force: T=mv2lT = \frac{mv^2}{l}.
  2. 25=0.25 v21.96⇒v2=19625 = \frac{0.25\,v^2}{1.96} \Rightarrow v^2 = 196
  3. vmax=14v_{max} = 14 m/s, so the answer is (a).
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