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JEE Main 2022 (26 Jun, Shift 1) · Motion Under Gravity

Motion Under Gravity question from JEE Main 2022 (26 Jun, Shift 1)

Q21JEE Main 2022 · 26 JUN · SHIFT 1Easy

Motion Under Gravity

A ball of mass 0.5 kg is dropped from the height of 10 m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ________ m. [Use g = 10 m/s2]

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. Need v=g=10v = g = 10 m/s (numerically); mass does not matter.
  2. Distance fallen: s=v22g=10020=5s = \frac{v^2}{2g} = \frac{100}{20} = 5 m
  3. Height above ground =10−5=5= 10 - 5 = 5 m
  4. So the answer is 5 m.
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