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JEE Main 2014 (19 Apr, Shift 1) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from JEE Main 2014 (19 Apr, Shift 1)

Q74JEE Main 2014 · 19 APR · SHIFT 1Medium

Angular Momentum & its Conservation

A ball of mass 160 g is thrown up at an angle of 60° to the horizontal at a speed of 10 ms−1{}^{-1}. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly (g = 10 ms−2{}^{-2})

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Answer: (b)

  1. At the top, v=ucos⁡60∘=5v=u\cos60^\circ=5 m/s (horizontal), height H=u2sin⁡260∘2g=100×3/420=3.75H=\frac{u^2\sin^2 60^\circ}{2g}=\frac{100\times3/4}{20}=3.75 m.
  2. L=mvH=0.16×5×3.75L=mvH=0.16\times5\times3.75
  3. L=3.0L=3.0 kg m²/s
  4. So the answer is (b) 3.0 kg m²/s.
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