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MHT CET 2023 (10 May, Shift 2) · Spring & Elastic Energy

Spring & Elastic Energy question from MHT CET 2023 (10 May, Shift 2)

Q9MHT CET 2023 · 10 MAY · SHIFT 2Medium

Spring & Elastic Energy

A ball of mass 'm\text{m}' is dropped from a height 's\text{s}' on a horizontal platform fixed at the top of a vertical spring. The platform is depressed by a distance 'hh'. The spring constant is ( g=\text{g} = acceleration due to gravity)

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Answer: (b)

  1. The ball falls a total height s+hs + h; all this PE is stored in the spring at maximum depression.
  2. mg(s+h)=12kh2mg(s + h) = \frac{1}{2}kh^2
  3. So the answer is (b) k=2mg(s+h)h2k = \frac{2mg(s+h)}{h^2}.
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