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JEE Main 2022 (27 Jul, Shift 1) · Comparing Two Projectiles

Comparing Two Projectiles question from JEE Main 2022 (27 Jul, Shift 1)

Q20JEE Main 2022 · 27 JUL · SHIFT 1Medium

Comparing Two Projectiles

A ball of mass m is thrown vertically upward. Another ball of mass 2m2m is thrown at an angle θ\theta with the vertical. Both the balls stay in air for the same period of time. The ratio of the heights attained by the two balls respectively is 1x\frac{1}{x}. The value of x is _____________.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

  1. Time of flight T=2uygT = \frac{2u_y}{g} depends only on the vertical component uyu_y (not on mass).
  2. Same TT means same uyu_y, so same height H=uy22gH = \frac{u_y^2}{2g}.
  3. Ratio 1x=1⇒x=1\frac{1}{x} = 1 \Rightarrow x = 1
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