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MHT CET 2024 (15 May, Shift 2) · Viscosity & Stokes' Law

Viscosity & Stokes' Law question from MHT CET 2024 (15 May, Shift 2)

Q9MHT CET 2024 · 15 MAY · SHIFT 2Medium

Viscosity & Stokes' Law

A ball rises to surface at a constant velocity in liquid whose density is 3 times greater than that of the material of the ball. The ratio of force of friction acting on the rising ball to its weight is

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Answer: (a)

Ball rises at constant velocity, so viscous force acts downward: $B = W + F$ .
$B = V(3\rho)g = 3W$
$F = 3W - W = 2W \Rightarrow F : W = 2 : 1$
So the answer is (a) $2 : 1$ .

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