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MHT CET 2024 (2 May, Shift 2) · Viscosity & Stokes' Law

Viscosity & Stokes' Law question from MHT CET 2024 (2 May, Shift 2)

Q10MHT CET 2024 · 2 MAY · SHIFT 2Medium

Viscosity & Stokes' Law

A ball rises to surface at a constant velocity in liquid whose density is 4 times greater than that of the material of the ball. The ratio of the force of friction acting on the rising ball and its weight is

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Answer: (a)

Ball rises at constant velocity, so viscous force acts downward: $B = W + F$ .
$B = V(4\rho)g = 4W$
$F = 4W - W = 3W \Rightarrow F : W = 3 : 1$
So the answer is (a) $3 : 1$ .

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